Homework Help is Here – Start Your Trial Now!
Math
Advanced Math
I think my derivation is wrong because I can’t find the critical points (I’m getting complex numbers instead of real numbers) can you show me how to derive this and get critical points

I think my derivation is wrong because I can’t find the critical points (I’m getting complex numbers instead of real numbers) can you show me how to derive this and get critical points

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section4.5: Rational Functions
Problem 8E
See similar textbooks
icon
Related questions
Question
I think my derivation is wrong because I can’t find the critical points (I’m getting complex numbers instead of real numbers) can you show me how to derive this and get critical points
f(x)=2x-11-x²+2x 2-x (1) dom f=\{2} asymptotes: lim f(x) = +os, lim f(x) = -00 8448 8154 (17) f(x) = I lim_ f(x) = +∞0₁ 2-2 2(x-1)-x²+2x 2-x 2-2+ -x²+4x-2 2-2 2(-x+1)=x²+2x = -2²-2 2-x 2-2 -2²-2 2-2 = -∞0 ⇒x=2 is a vertical asymptote -x² +42-2 → (-2x+4)(2-x) − (−x²+4x−2)(-1) = x²-4x+b ⇒>> 2-2 (2-x)² (2-2)² (-22) (2-2) - (-2²-2)(-1) →> (2-2)² - x²-4x-2 (2-2)²
Transcribed Image Text:f(x)=2x-11-x²+2x 2-x (1) dom f=\{2} asymptotes: lim f(x) = +os, lim f(x) = -00 8448 8154 (17) f(x) = I lim_ f(x) = +∞0₁ 2-2 2(x-1)-x²+2x 2-x 2-2+ -x²+4x-2 2-2 2(-x+1)=x²+2x = -2²-2 2-x 2-2 -2²-2 2-2 = -∞0 ⇒x=2 is a vertical asymptote -x² +42-2 → (-2x+4)(2-x) − (−x²+4x−2)(-1) = x²-4x+b ⇒>> 2-2 (2-x)² (2-2)² (-22) (2-2) - (-2²-2)(-1) →> (2-2)² - x²-4x-2 (2-2)²
Expert Solution
steps

Step by step

Solved in 3 steps with 12 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer