I want solution flowchart Start Step 1: Declare Student_Name[10], Student_Score[10][5],i=0,j=0,sum=0 Step 2: for i=0 to 9 Step 3: Get Student_Name[i] Step 4: for j=0 to 4 Step 5: Get Student_Score[i][j] Step 6: sum=sum+Student_Score[i][j] Step 7: End for Step 8: Print "Name= ",Student_Name[i] "Average=", (sum/5) Step 9: End for End

I want solution flowchart Start Step 1: Declare Student_Name[10], Student_Score[10][5],i=0,j=0,sum=0 Step 2: for i=0 to 9 Step 3: Get Student_Name[i] Step 4: for j=0 to 4 Step 5: Get Student_Score[i][j] Step 6: sum=sum+Student_Score[i][j] Step 7: End for Step 8: Print "Name= ",Student_Name[i] "Average=", (sum/5) Step 9: End for End

Programming Logic & Design Comprehensive

9th Edition

ISBN:9781337669405

Author:FARRELL

Publisher:FARRELL

Chapter4: Making Decisions

Section: Chapter Questions

Problem 15RQ

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You are given n users, and their times that they log in and out of a website: You are interested in which users are on the site at the same time. For example, you are given the following 5 users and their times: User 1- In: 1 Out: 4 User 2- In: 2 Out: 5 User 3- In: 7 Out: 8 User 4- In: 9 Out:10 User 5- In: 6 Out:10 This gives the distinct users that are on the site at the same time as (1,2), (4,5), and (3,5). Given n elements, write pseudocode for an algorithm that would take n^2 time to compute the number of pairs of users that are on the site at the same time
Convert Python to R costs = pd.read_csv("Inpatient_Prospective_Payment_System__IPPS__Provider_Summary_for_the_Top_100_Diagnosis-Related_Groups__DRG__-_FY2011.csv") costs = costs.rename(columns = {'DRG Definition': 'DRG',' Average Total Payments ': 'Total_Cost', # Note spaces around ' Average Total Payments '' Total Discharges ': 'Count_Discharges'}) # Note spaces around ' Total Discharges ' costs[['DRG_Code', 'DRG_Description']] = costs['DRG'].str.split(' - ', expand = True) # Note spaces around ' - 'costs = costs.drop(['DRG'], axis = 1) costs['Avg_DRG_Cost'] = costs.groupby('DRG_Code')['Total_Cost'].transform(np.mean)costs['Cost_Diff'] = costs['Total_Cost'] - costs['Avg_DRG_Cost'] top_drgs = (costs.groupby('DRG_Code')['Count_Discharges'].sum().sort_values(ascending = False)) top_drgs.index[0] (costs.query("DRG_Code == '470' and 'Provider State' == 'CA'").to_csv("Hip_Replacement_Costs_by_Hosp.csv", index = False))
Hi! I get this error message with this code. Can you help me? # Write your solution here def who_won(game_board): # Initialize counters for each player's encircled area player1_area = 0 player2_area = 0 # Iterate through each square in the game board for i in range(len(game_board)): for j in range(len(game_board[i])): # Check if the square is encircled by player 1's game pieces if game_board[i][j] == 1: # Check if all four surrounding squares are also player 1's game pieces if (i > 0 and game_board[i-1][j] == 1) and (i < len(game_board)-1 and game_board[i+1][j] == 1) and (j > 0 and game_board[i][j-1] == 1) and (j < len(game_board[i])-1 and game_board[i][j+1] == 1): player1_area += 1 # Check if the square is encircled by player 2's game pieces elif game_board[i][j] == 2: # Check if all four surrounding squares are also player…
You have given a list of q queries and for every query, you are given an integer N. The task is to find how many numbers less than or equal to N have numbers of divisors exactly equal to 3. Example 1: Input: q = 1 query[0] = 6 Output: 1 Explanation: There is only one number 4 which has exactly three divisors 1, 2 and 4 and less than equal to 6. Example 2: Input: q = 2 query[0] = 6 query[1] = 10 Output: 1 2 Explanation: For query 1 it is covered in the example 1. query 2: There are two numbers 4 and 9 having exactly 3 divisors and less than equal to 10. Your Task: You don't need to read input or print anything. Your task is to complete the function threeDivisors() which takes an integer q and a list of integer of size q as input parameter and returns the list containing the count of the numbers having exactly 3 divisors for each query.Expected Time Complexity: O(NlogN),Expected Auxiliary Space: O(N), where N is min(10^6,N) Constraints :1 <= q <= 1031 <= query[i] <= 1012 //…
1. Consider the following NFA N: :+ nfa N { Q={q1,q2,q3,q4,q5} S={a,b} q0=q1 d(q1,a)={q2} d(q2,\e)={q3} d(q2,a)={q1} d(q3,\e)={q1} d(q3,b)={q4} d(q4,b)={q5} d(q5,b)={q3} F={q3} } Question: Use !{the algorithm from the notes} to construct an NFA N_2 that does not use \e-transitions and that is !{@eqnt} to N.
Question 2: You are given a grid of size N x N where each cell contains a non-negative integer. You need to find the maximum sum of a path from the top-left corner to the bottom-right corner. You can only move to the right or down from each cell. Apply a dynamic programming algorithm to solve this problem and explain your approach 1. Write a text explanation of your solution in a step by step. 2. Provide a Java solution code of your proposed solution and run it on the following input int grid={(1, 3, 1}, {1, 5, 1}, {4, 2, 1}};
A data set has 4 columns--index, CUSTOMER_EMAIL, Net Revenue, and Year. For each year we need the following information: New Customer Revenue e.g., new customers not present in previous year only Lost Customers New Customers Total Customers Previous Year Total Customers Current Year Please implement it using python.
[Medium] Suppose, you have been given a non-negative integer which is the height of a ‘house of cards’. To build such a house you at-least require 8 cards. To increase the level (or height) of that house, you would require four sides and a base for each level. Therefore, for the top level, you would require 8 cards and for each of the rest of the levels below you would require 5 extra cards. If you were asked to build level one only, you would require just 8 cards. Of course, the input can be zero; in that case, you do not build a house at all. Complete the recursive method below to calculate the number of cards required to build a ‘house of cards’ of specific height given by the parameter. public int hocBuilder (int height){ // TO DO } OR def hocBuilder(height):
Complete the Truth Tables. STATEMENT: (? ∧ ?) ∨ ~? p q p ∧ q ∼p (p ∧ q)∨∼p T T T F F T F F STATEMENT: ~? → (~? ∨ ?) p q ~? ~q ~?∨q ~q→ (~?∨q) T T T F F T F F
REDUCE ( NEED ONLY HANDWRITTEN SOLUTION PLEASE OTHERWISE DOWNVOTE).ANSWER IN MINIMUM THREE STEPS.
Only Typing answer In this task you are asked to construct a table showing the sequence of numbersfrom 0 to a maximum value as specified by the user. Within the table, if the number in the cell is a highlighted (e.g., blue in thescreenshot below) when it is divisible by a number that is also specifiedbytheuser, known as the divisor. For example, the user could input for the maximumavalue of 100 and for the divisor a value of 23; this should result in the cellscontaining the values: 0, 23, 46, 69 and 92; being highlighted.
Need Help with Octave: function [w, t, flag] = margin_pcpt(X, y, max_iter, max_margin)[m, n] = size(X);flag = 0;w = zeros(n, 1);t = 1;while (t < max_iter) && (flag == 0)% Your tasks: % 1. searches for violation point p such that % (a) the label disagrees with p*w; OR % (b) the distance between p and seperation line is too close, i.e. % p*(w./norm(w, 2)) <= max_margin % 2. update the seperation plane vector w % 3. if there is no more violation point, set flag = 1. t = t + 1;end% as a good habit: normalise the seperation vector by it's normw = w./norm(w, 2);end