I. In the fruit fly Drosophila melanogaster, tan body color (B) is dominant to black (b), and dark red eyes (E) is dominant to bright orange (e). A black fly, heterozygous for eye color (Fly #1) is crossed to an orange eyed fly, heterozygous for body color (Fly #2). What are... Genotypes of the parents? Gametes from each parent? Ratios of gametes from each parent? Complete the following Punnett square. Indicate gamete genotypes from each parent and all offspring genotypes. Fly #1 What proportion of offspring are... Tan & dark red? Tan & orange? Black & dark red? Black & orange? Probability (P) of Aa Bb Dd = P (Aa) B. | || C. II. What is the probability that this pair of parents will produce the indicated offspring? Aa Bb DD x aa Bb Dd Aa Bb Dd. Punnett squares for each trait can help with this! III IV Mode of inheritance = I BIO 340 ACTIVITY #3: HYBRID CROSSES, PROBABILITY & PEDIGREES Name (Last, First) III. For each of these three pedigrees, determine the likely mode of inheritance and the probability that individual will express the trait. A. || O III IV Mode of inheritance = O I 11 III #1 O Mode of inheritance = #1 IV " ОПОDO #1 Fly #2 오ㅜㅁ +000 x P (Bb) x #2 □-O- #2 ■-O #2 x P (Dd) O P() expresses trait = P() expresses trait = 우ㅜ OD P() expresses trait = 1 2

Biology: The Dynamic Science (MindTap Course List)
4th Edition
ISBN:9781305389892
Author:Peter J. Russell, Paul E. Hertz, Beverly McMillan
Publisher:Peter J. Russell, Paul E. Hertz, Beverly McMillan
Chapter13: Genes, Chromosomes, And Human Genetics
Section: Chapter Questions
Problem 8TYK: Another gene in Drosophila determines wing length. The dominant wild-type allele of this gene...
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I. In the fruit fly Drosophila melanogaster, tan body color (B) is dominant to black (b), and
dark red eyes (E) is dominant to bright orange (e). A black fly, heterozygous for eye color
(Fly #1) is crossed to an orange eyed fly, heterozygous for body color (Fly #2). What are...
Genotypes of the parents?
x #2
Gametes from each parent?
Ratios of gametes from each parent?
Complete the following Punnett square. Indicate gamete genotypes from each parent
and all offspring genotypes.
Fly #1
What proportion of offspring are...
Tan & dark red?
Tan & orange?
Black & dark red?
Black & orange?
Probability (P) of Aa Bb Dd = P (Aa)
A.
B.
II. What is the probability that this pair of parents will produce the indicated offspring?
Aa Bb DD x aa Bb Dd
Aa Bb Dd. Punnett squares for each trait can help with this!
I
C.
Mode of inheritance =
|| O
IV
BIO 340 ACTIVITY #3: HYBRID CROSSES, PROBABILITY & PEDIGREES
Name (Last, First)
III. For each of these three pedigrees, determine the likely mode of inheritance and the
probability that individual will express the trait.
I
"O
III
IV
Mode of inheritance =
||
I
-8-8-8
x P (Bb)
#1
#1
--O
Mode of inheritance =
#1
Fly #2
우ㅜ
IV O
Tº
#2
OD
#2
O
x P (Dd)
O
P() expresses trait =
P() expresses trait =
OD
P() expresses trait =
1
2
Transcribed Image Text:I. In the fruit fly Drosophila melanogaster, tan body color (B) is dominant to black (b), and dark red eyes (E) is dominant to bright orange (e). A black fly, heterozygous for eye color (Fly #1) is crossed to an orange eyed fly, heterozygous for body color (Fly #2). What are... Genotypes of the parents? x #2 Gametes from each parent? Ratios of gametes from each parent? Complete the following Punnett square. Indicate gamete genotypes from each parent and all offspring genotypes. Fly #1 What proportion of offspring are... Tan & dark red? Tan & orange? Black & dark red? Black & orange? Probability (P) of Aa Bb Dd = P (Aa) A. B. II. What is the probability that this pair of parents will produce the indicated offspring? Aa Bb DD x aa Bb Dd Aa Bb Dd. Punnett squares for each trait can help with this! I C. Mode of inheritance = || O IV BIO 340 ACTIVITY #3: HYBRID CROSSES, PROBABILITY & PEDIGREES Name (Last, First) III. For each of these three pedigrees, determine the likely mode of inheritance and the probability that individual will express the trait. I "O III IV Mode of inheritance = || I -8-8-8 x P (Bb) #1 #1 --O Mode of inheritance = #1 Fly #2 우ㅜ IV O Tº #2 OD #2 O x P (Dd) O P() expresses trait = P() expresses trait = OD P() expresses trait = 1 2
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