Can you solve (i) and present the answers as table I sent. Thank you Subproblem (-) | Answers7(t) = (p(t), v(t)) (... ,.)from t = . to t = ..(a)Sket ch of the curve1= (t) = ..-;y = (t) = ..:(b)(c)+y2 = .;12 + y2 =.. far all te la, b);(d)V2 + y2 dtdt =.. + C;(e)len(7) =(f)len(7) a 2. (Lengths of Smooth Curves). For each of the following parametric curvesSz= +(t),y = (1),(a । ६ b),(a) sketch the curve;(b) find z' = y'(t) and y' = (t);(c) find z'2 + y2, and then find and simplify VI2 + yr2 (the length of the tangent vector y(t), the "speed");(d) find the indefinite integral V2 + y7 dt;(e) find the length of y by evaluating the integral(f) round your result in (e) to five decimal places.= 9t – sin(9t),( coe(24),(i)from t =0 to 2n/9;from 0tot=1/2;y =1- cos(9t)

Since you are asking multiple subparts, we are answering only the first three subparts for you.…

Answered: I=9 - nin(94), (i) y-1- con(9t) from t0…

Math

Calculus

I=9 - nin(94), (i) y-1- con(9t) from t0 to 2n/9;

Calculus: Early Transcendentals

8th Edition

ISBN:9781285741550

Author:James Stewart

Publisher:James Stewart

Chapter1: Functions And Models

Section: Chapter Questions

Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...

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Equations and Inequations

Equations and inequalities describe the relationship between two mathematical expressions.

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A linear function can just be a constant, or it can be the constant multiplied with the variable like x or y. If the variables are of the form, x2, x1/2 or y2 it is not linear. The exponent over the variables should always be 1.

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Can you solve (i) and present the answers as table I sent. Thank you

Subproblem (-) | Answers
7(t) = (p(t), v(t)) (... ,.)
from t = . to t = ..
(a)
Sket ch of the curve
1= (t) = ..-;
y = (t) = ..:
(b)
(c)
+y2 = .;
12 + y2 =.. far all te la, b);
(d)
V2 + y2 dt
dt =.. + C;
(e)
len(7) =
(f)
len(7) a

2. (Lengths of Smooth Curves). For each of the following parametric curves
Sz= +(t),
y = (1),
(a । ६ b),
(a) sketch the curve;
(b) find z' = y'(t) and y' = (t);
(c) find z'2 + y2, and then find and simplify VI2 + yr2 (the length of the tangent vector y(t), the "speed");
(d) find the indefinite integral V2 + y7 dt;
(e) find the length of y by evaluating the integral
(f) round your result in (e) to five decimal places.
= 9t – sin(9t),
( coe(24),
(i)
from t =0 to 2n/9;
from 0tot=1/2;
y =1- cos(9t)

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