MACULATE COA. Determine whether or not f is continuous at a.1. f(x) = 2x² - 10; a = -4%3D2. f(x) = Vx+3; a = -7%3D3. f(x) =16 aX-4;a =-4%3Dx²+164. f(x) =x2-4x;a=0x2+4x%3D5. f(x) = {fx? - 3, xs-1a =-1%3Dlx=1, x> -1"

As per our guideline we supposed to answer only first three sub-parts we check at given point…

ia=-1 A. Determine whether or not f is continuous at a. 1. f(x) = 2x² – 10; a = -4 %3D 2. f(x) = Vx + 3; a = -7 %3D %3D 3. f(x) = ズー4 %3D x²+16 ;a=-4 4. f(x) = x2-4x %3D x2+4x = 0 ;a=0 3, x<-1 5. f(x) = { %3D :-1 lx-1, x>-

ia=-1 A. Determine whether or not f is continuous at a. 1. f(x) = 2x² – 10; a = -4 %3D 2. f(x) = Vx + 3; a = -7 %3D %3D 3. f(x) = ズー4 %3D x²+16 ;a=-4 4. f(x) = x2-4x %3D x2+4x = 0 ;a=0 3, x<-1 5. f(x) = { %3D :-1 lx-1, x>-

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter5: Inverse, Exponential, And Logarithmic Functions

Section5.3: The Natural Exponential Function

Problem 52E

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Question

MACULATE CO
A. Determine whether or not f is continuous at a.
1. f(x) = 2x² - 10; a = -4
%3D
2. f(x) = Vx+3; a = -7
%3D
3. f(x) =16 a
X-4
;a =-4
%3D
x²+16
4. f(x) =
x2-4x
;a=0
x2+4x
%3D
5. f(x) = {
fx? - 3, xs-1
a =-1
%3D
lx=1, x> -1"

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