Identify the addressing modes & the value of the register Ro for each of given instruction initial values of Ro= 1500, R1=3000, PC = 4000. ADDRESS VALUE 1000 1260 2000 1570 2900 1400 3000 1650 4000 1750 4102 1150 4500 1760 5000 1850
Q: Identify the addressing modes of following instructions. 11: MOV AL,BL 12: ADD AL[1010H]
A: Subject: Digital circuit and fundamentals of microprocessor Identify the addressing modes of…
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A: let us see the answer:-
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Q: Consider the following Figure of mips architecture, which instruction does have Operation 010
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Q: What is the MIPS instruction equivalent of the following 32 bit pattern? 1010 1110 0101 1001 0000…
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Q: When the CMP instruction sequence is executed, what is the final value for AL register ? MOV AL, 25h…
A: Answer is in step-2.
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A: The Answer is
Q: determine the time taken to execute the instruction if the clock frequency of 8085 is 10MHz. Lxi h,…
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Q: Given the number 0x12345678 in PIC18 and the starting address is 0x28 a.Write instruction sequence…
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Q: determine the time taken to execute the instruction if the clock frequency of 8085 is 10MHz. Lxi h,…
A: Find the required answer with calculation given as below :
Q: Given a bit pattern 0001 0001 0001 0000 0000 0000 0000 1011. what does it represent assuming it is…
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Q: Convert the following RISC-V branch instruction into machine code. Write your final answer in…
A: Convert the following RISC-V branch instruction into machine code.Write your final answer in…
Q: Suppose we have the instruction Load 1200. Given memory as follows: Memory 1000 1100 1200 800…
A: Please upvote, I am providing you the correct answer below. Please please. 1. Indirect…
Q: Explain (in one to two lines) the function of the instruction XCHG AX, BX, if AX = 5241H and BX =…
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Q: Draw timing diagram for the following instructions: i. Instruction: LHLD 1444 H Corresponding…
A: Answer : Immediate Addressing Mode : This LXI is an load instruction ,so called as immediate…
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Q: select the correct answer Q1) if you know the ss-1245H ,DS-5678H, BP- 3ACDH ,BX-23ADH,…
A: Here, I have to choose an option to the above question.
Q: Question 01 Convert the given Machine Instructions into MIPS Assembly instruction. Also provide the…
A: 1) add $8,$17,$18 Or add $t0,$s1,$s2 2) Lw $8,0x20($19) Or lw $t0,0x20($s3)
Q: MOV AL,[2000 H] * Direct addressing mode Register addressing mode Register indirect addressing mode…
A: As per our guidelines we are supposed to answer only one question.kindly repost other question as a…
Q: The content of AC in the basic computer is hexadecimal A937 and the initial value of E is 1.…
A: The content of AC in the basic computer is hexadecimal A937 and the initial value of E is 1.…
Q: Please find the Machine code for the instruction: Mov DX, [BX+SI] . Consider the Opcode for a Mov…
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Q: Given the instruction: j Finish where its 32-bit format is 0x08100008 and its address in text…
A: As mentioned above the user is using the Mips language, and in the pseudo direct addressing which…
Q: Evaluate the effect of the instruction LDR r5, [r7, #4], given the initial values below. Give the…
A: The answer and the explanation is given below:
Q: When the CMP instruction sequence is executed, what is the final value for AL register ? MOV AL, 25h…
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Q: A PC-relative mode branch instruction
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Q: Suppose we have the instruction Load 800. Given memory as follows (assume all numbers are decimal):…
A: Please upvote. I am providing you the correct answer below. Please please please.
Q: An ADD instruction stores a value 7308h at offset value 9F71h. if the computed address is 7CB31h,…
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Q: If the bit pattern 0×0C000000 is placed into the Instruction Register, what MIPS instruction will be…
A: Placing bit pattern into the Instruction Register: The given 32-bit pattern is written in binary…
Q: When the CMP instruction sequence is executed, what is the final value for AL register? MOV AL, 25h…
A: Explanation 1) The CMP instruction compares two operands. It is generally used in conditional…
Q: Identify the values of opcode, D, W, mod, REG, and R/M of each instruction Convert binary values to…
A: 1. opcode: 8B, D: 1, W: 0, mod: 3, REG: 3, R/M: 5 2. opcode: 8B, D: 0, W: 0, mod: 3, REG: 1, R/M: 2…
Q: the given machine code to 6809 instruction: ED 89 01 23 STD $0123, X ADDD 0123, X STD #0123, X STD…
A: 1) ADDD 0123, X
Q: 7. Given the number 0x123456 in PIC18 and the starting address is 0x123 a. Write instruction…
A: Multiplying by 8 means left shifting value 0x123456 stored in 0x123 by 3 bits.…
Q: How many bus cycles will be needed for the instruction: MOV AH, [4312H] ) Instruction is invalid…
A: Bus cycles will be needed for the instruction:MOV AH,[4312H]
Q: How many address lines are used by the 8088 for the instruction IN AL, 14? A) 1 B) 20 C) None D)…
A: In 8088, the size of the address lines is 16 bits. Now, in this instruction IN AL, 14, the input to…
Q: Convert the following RISC-V branch instruction into machine code. Write your final answer in…
A: Here is the code:-
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Q: The instruction, MOV AX, 0005H belongs to the address mode register direct immediate register…
A: Here have to determine correct option for question about address mode.
Q: PC 21 R C 275 351 200 Address 275 276 277 349 350 351 352 400 500 501 600 Memory Load to AC Mode…
A: The answer is
Q: Given two 1-Byte numbers at locations 8050H and 8051H. Write 8085 instruction to add the data at…
A: Let the memory at 8050H and 8051H be 04H and 08H, then the output at 8052H should be 04H + 08H =…
Q: Q2: Give the addressing mode for each of the following instructions: 1. MOV [CL+1234H], DH…
A: Find the required answer given as below :
Q: Select the instruction sequence that will divide -276 by 10 and store the result in a 16-bit…
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Q: Select the machine code equivalent for the following Branch Instruction. Address Assembly Code 0x210…
A: The solution to the given problem is below.
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- Most Intel CPUs use the __________, in which each memory address is represented by two integers.Registers in RISC-V are 64-bit. For the sake of simplicity, consider the following instructions operating on 32-bit registers. Assume that registers x5 and x6 hold the values 0xBBBBBBBB and 0x00000000, respectively. What is the value in x6 for the followingslli x6, x5, 6 Using the result from the part above, what is the value in x6 for the following instruction. srli x6, x6, 6Question/ program give below run on 8086 used to add two 32-bit number. Fill the missing code to store the result immediately in location start with 30042 3000[ 12 4000 [ 12 3004[ 24 3001 [ 11 4001 [ 10 3005 [ 21 3002{ 02 4002 [ 21 3006( 23 3003 01 4003 [C04 3007 05 Mov AX.3000h Fig (1) memory data segment Mov DS, AX Mov AX.4000 MovES, AX Mov SI,0000h Mov DI0000h Mov CX,04h NEXT: Mov AX, [SI] Mov BX, [DI] ADD AX, BX,
- Write out how to solve the following code using any addressing mode for (3,3) GPR. a[] is address0x100, y is address 0x300, z is address 0x400, and x is using r0. Write comments besides each line ofcode. Short a[50];Int y,z;for( x=0; x<20; x++){y = a[x + 3];z = y + a[x+10];}Convert given code to LEGv8 code:int f, g, y //global 64-bit variablesint sum (int a, int b) { // at memory address X0+1000.return (a +b)} int main (void) // at memory address X0 + 800{f=2;g=3;y= sum (f, g);return y;}Convert this code, making valid assumptions about registers and register use. Notethat brackets and global variable declarations are not affecting the addresses of the instructionsin memory.Consider the following hexadecimal readout: 000000 8A00 8E00 CFA1 48BF 7900 3202 9015 AD34 000010 0218 6D30 028D 3402 AD35 0288 3102 8D35 000020 0E30 0290 DAEE 3102 4C00 0200 0040 004B Refer to the first byte of memory shown above, address 000000. Assume that this byte is used to store an 8-bit unsigned integer. What is the decimal value stored in this byte? Group of answer choices 138 -27 22,842 66
- With your knowledge in memory addressing mods and using the given opcodesSTCH = OX54Buffer = 1000 0101 0100(00) 1(x) 011 0000 0000 0000() What will be the target address?Question 2: Write the MIPS code for the given Hexadecimal Machine Code that starts at memory address 0x40000. Line1: 0x0080082A Line2: 0x14200002 Line3: 0x2084FFFF Line4: 0x08010005 Line5: 0x20840001 Line6: 0x1480FFFA Line7: 0x03E00008 Line8: 0x0C010000This question is on Computer Architecture. Translate the following arithmetic and logical expressions written in C programming language intoinstructions sequences written in MIPS Assembly language. You may assume that the values (orbase addresses) of the variables a, b, c, and d are in the general-purpose registers $s0, $s1,$s2, and $s3. 1. d[3] = a - b + c[7];2. c[5] = (a << 3) & (b >> 2);Here, <<, >>, and & indicate the bitwise left-shift, right-shift, and AND operations respectively.
- 25: . Find the time delay in the following program if the crystal frequency is 1 MHz. Do not ignore the time delay due to the first and last instruction. DELAY: LDI R16, 30 AGAIN: LDI R17, 35 HERE: NOP NOP DEC R17 BRNE HERE DEC R16 BRNE AGAIN RET 26: Write a program to display 2 on 7 segment. A 7 segment is connected to PortD.Find the machine codes of following 8085 instructions and in each case identify the opcodepart, and register/ memory reference bits. Also mention the length of opcode, number of bytesin the instruction.MOV A, M;MVI C, data;PUSH B;ADC B;XRA L;JNZ addressLDAX B Translate the following Assembly program of 8085 into machine code (hex format) MVI C, 20LXI H, 1500hMVI A, 00next; MOV B, MADC BINX HDCR CJNZ nextSTA 1600hHLTAssume that the program is to be stored in memory starting at address 1000h Find out the number of machine cycles and the number of T-states taken by the following8085 instructions. In each case give an explanation for your answer.(i) ADC D(ii) ADI 05(iii) JMP 1500h(iv) JNZ 1500h(v) LDAX B(vi) MOV A, B(vii) LDA 1300h Draw a complete connection diagram of a computer system with 8085 as processor, a four 1KRAM, and four 1K ROM chips. Give the address range for each RAM and ROM chips. Translate the sumArray function (written in C below) to 8085 assembly…3) The 8-bit register AR, BR, CR, and DR initially have the following values: [5]AR = 11010110; BR = 11100111; CR = 10110001; DR = 10111010Determine the 8-bit values in each register after the execution of the following sequenceof microoperations.AR AR + BR Add BR + ARCR CR AND DR, BR BR + 1 AND DR to CR, Increment BRAR AR - CR Subtract CR from AR