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If 3x2 + yx = 9, what is -? dx dx dx = = = 11 -6x-y² 2.xy -6x+y² 2x -6x-y2 2x² 6x-y2 2y 59

If 3x2 + yx = 9, what is -? dx dx dx = = = 11 -6x-y² 2.xy -6x+y² 2x -6x-y2 2x² 6x-y2 2y 59

Algebra for College Students
Algebra for College Students
10th Edition
ISBN:9781285195780
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter12: Algebra Of Matrices
Section12.CR: Review Problem Set
Problem 37CR
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If 3x² + y²x = 9, what is dy -? dx O O O dx O dx dy dx dy dx dy | = dx = If f(x) = x²log4(x), what is dy dx -6x-y² 2xy -6x+y² 2x -6x-y² 2x² 6x-y² 2y + 2xlog4(x) 2xlog4 (x) In 4 In 4-log(x) 4 + log(x) g'(x) = -³/2 og'(x) = -3/1/2 og'(x) = -1/2/2 g'(x) = //2 If f(x) = , and x+2 g(x) = f(x), what is g'(x)? 58 If f(x) = log 7(x2), what is dx 54 If f(x) = +2, and 56 8(x) = -1 (x), what is the slope of the curve g(x)=f(x) at the point (5, 1)? || x In 7 x In 7 x In 7 og'(5) = -10 g'(5) = 1 O g'(5) = -1/0 g'(5) = 10 55 If f(x) = (x² - 4)sin-¹(x), what is f'(x)? ○ f'(x) = √1-x² 57 f'(x) = x + 2xsin¯¹(x) f'(x) = -2xsin-¹(x) f'(x) = + sin-¹ (x) √1-x² VI-x - 2xsin-¹(x) 59 If f(x) = (-2x)tan-¹ (x³), what is f'(x)? 10 f'(x) = -2(3x³ + tan-1 ¹x³) 1+(x³)² f'(x) = -2( + tan-¹x³) 1+x³ f'(x) = 2 (3-tan-¹x³) f'(x) = 3-tan-¹x³
Transcribed Image Text:If 3x² + y²x = 9, what is dy -? dx O O O dx O dx dy dx dy dx dy | = dx = If f(x) = x²log4(x), what is dy dx -6x-y² 2xy -6x+y² 2x -6x-y² 2x² 6x-y² 2y + 2xlog4(x) 2xlog4 (x) In 4 In 4-log(x) 4 + log(x) g'(x) = -³/2 og'(x) = -3/1/2 og'(x) = -1/2/2 g'(x) = //2 If f(x) = , and x+2 g(x) = f(x), what is g'(x)? 58 If f(x) = log 7(x2), what is dx 54 If f(x) = +2, and 56 8(x) = -1 (x), what is the slope of the curve g(x)=f(x) at the point (5, 1)? || x In 7 x In 7 x In 7 og'(5) = -10 g'(5) = 1 O g'(5) = -1/0 g'(5) = 10 55 If f(x) = (x² - 4)sin-¹(x), what is f'(x)? ○ f'(x) = √1-x² 57 f'(x) = x + 2xsin¯¹(x) f'(x) = -2xsin-¹(x) f'(x) = + sin-¹ (x) √1-x² VI-x - 2xsin-¹(x) 59 If f(x) = (-2x)tan-¹ (x³), what is f'(x)? 10 f'(x) = -2(3x³ + tan-1 ¹x³) 1+(x³)² f'(x) = -2( + tan-¹x³) 1+x³ f'(x) = 2 (3-tan-¹x³) f'(x) = 3-tan-¹x³
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