* If A = [1 2 3; 4 5 6; 7 8 9;0 0 0], then size(A)= O 44 34 O 33 O 43 Other:
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- Programming in C#: Write a console-based application that displays every perfect number from 1 through 10000. A number is perfect if it equals the sum of all the smaller positive integers that divide evenly into it. For example, 6 is perfect because 1, 2, and 3 divide evenly into it and their sum is 6. Use format strings(field size 8, right alignment) to show all perfect numbers. Display the results as seen below. 6 28 496 8128in c# Write a console app that inputs a sentence from the user (assume no punctuation), then determines and displays ONLY THE DUPLICATE words in alphabetical order. Treat uppercase and lowercase letters the same. [Hint: You can use string method Split with no arguments, as in sentence.Split(), to break a sentence into an array of strings containing the individual words. By default, Split uses spaces as delimiters. Use string method ToLower before calling Split.]Please help with this c++ problem Assignment 6 - Monkey Food In the Gaddis textbook read Chapter 8 sections 8.1-8.9 before starting this assignment. This assignment is Programming Challenge 4 from Chapter 8 of the textbook. A local zoo wants to keep track of how many pounds of food each of its three monkeys eats each day during a typical week. Write a program that stores this information in a two-dimensional 3 x 7 arrray, where each row represents a different monkey and each column represents a different day of the week. The program should first have the user input the data for each monkey from the keyboard. The number of pounds of food eaten by one monkey in one day should be a floating-point value. Input Validation: Do not accept negative numbers. Then your program should create a report that includes the following information: A nicely-formatted table with a row for each monkey and a column for each day of the week showing the amount of food eaten by that monkey on that day. Be…
- >> IN C PROGRAMMING LANGUAGE ONLY << COPY OF DEFAULT CODE, ADD SOLUTION INTO CODE IN C #include <stdio.h>#include <stdlib.h>#include <string.h> #include "GVDie.h" int RollSpecificNumber(GVDie die, int num, int goal) {/* Type your code here. */} int main() {GVDie die = InitGVDie(); // Create a GVDie variabledie = SetSeed(15, die); // Set the GVDie variable with seed value 15int num;int goal;int rolls; scanf("%d", &num);scanf("%d", &goal);rolls = RollSpecificNumber(die, num, goal); // Should return the number of rolls to reach total.printf("It took %d rolls to get a \"%d\" %d times.\n", rolls, num, goal); return 0;}Bulgarian solitaire def bulgarian_solitaire(piles, k): You are given a row of piles of pebbles, all identical, and a positive integer k so that the total number of pebbles in these piles equals k*(k+1)//2, the arithmetic sum formula that equals the sum of positive integers from 1 to k. Almost as if intended as a metaphor for the bleak daily life behind the Iron Curtain, all pebbles are identical and you don't have any choice in your moves. Each move picks up one pebble from each pile (even if doing so makes that pile vanish), and creates a new pile from the resulting handful. For example, starting with[7, 4, 2, 1, 1], the first move turns this into [6, 3, 1, 5]. The next move turns that into [5, 2, 4, 4], which then turns into the five-pile configuration [4, 1, 3, 3, 4], and so on. This function should count how many moves are needed to convert the given initial piles into the goal state where each number from 1 to k appears as the size of exactly one pile, and return that count. These…Count the number of elements in a that have values between 10 and 20 inclusive. int count=0; for(int i=0;i<10,i++) { if(a[i]>=10 && a[i]<=20) { count=count+1; } System.out.println(“count… = “+ count); }
- Following code is for 4×4 tic toc toe game covert this code in to 3×3 players. Code #include <iostream> using namespace std; class Board { char board[4][4]; public: Board() { for(int i=0;i<4;i++) { for(int j=0;j<4;j++) { board[i][j]='_'; } } } void printBoard() { for(int i=0;i<4;i++) { for(int j=0;j<4;j++) { cout<<board[i][j]<<'|'; } cout<<endl; } cout<<endl; } int setPosition(char choice) { while(1) { int row,column; cout<<"Please enter the row and column"<<endl; cin>>row>>column; if(board[row][column]=='_') { board[row][column]=choice; break; } else { cout<<"Position is taken"<<endl; } } } char getPosition() { for(int i=0;i<4;i++) { for(int j=0;j<4;j++) { return board[i][j]; } } } int checkHorizontal(char choice) { int count; for(int i=0;i<4;i++) {…cout<<"Team name is is "< cout<<"The team got "<<no for (int i=0;i<no_of_medal cout<<medals[i]<< cout<<endl; Sport_team::~Sport_team() { delete []medals; cout<<"Memory free"<<endl } void f(Sport_team o) { cout<<"Team info print by o.print(); } void main() { Sport_team s; string n; int m; cout<<"Enter the sport's cin >>n ; cout<<"Enter number of me cin>>m; . set(n, m) ; s.print(); f(s) ; s.print();Q // Write a program in C++ language that enters a number of integer numbers into a singular matrix whose size is renewed after asking the user about the number of numbers he wants to enter, then he collects these numbers and prints the result on the screen
- def small_index(items: list[int]) -> int:"""Return the index of the first integer in items that is less than its index,or -1 if no such integer exists in items.>>> small_index([2, 5, 7, 99, 6])-1>>> small_index([-5, 8, 9, 16])0>>> small_index([5, 8, 9, 0, 1, 3])3""""" Hosoya triangle (originally Fibonacci triangle) is a triangular arrangement of numbers, where if you take any number it is the sum of 2 numbers above. First line is always 1, and second line is always {1 1}. This printHosoya function takes argument n which is the height of the triangle (number of lines). For example: printHosoya( 6 ) would return: 1 1 1 2 1 2 3 2 2 3 5 3 4 3 5 8 5 6 6 5 8 The complexity is O(n^3). """ def hosoya(height, width):.This is what I currently have : void displaySentence(char * sentence); char * sentence;
