If a 350-lb load is suspended by two chains as shown in the figure to the right. What is the magnitude of the force each chain must be able to support? V 45 45° 350 lb Let F, and F, denote the forces exerted by the chains on the load and let F, be the downward force due to the weight of the load. Place the vectors in a standard coordinate system shown to the right. If the load is in equilibrium (so the chains and load are stationary), which of the following equations should stand? O A. -F, - F2 + F3 = 0 O B. F, +F2 +F3 = 0 OC. F, +F2 -F3 = 0 O D. F, -F2 +F3 = 0 F,

Q: 4) Find the magnitude and direction of the vector i that has components v4 = –1525 and vy = -8402.

A:

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A: Here, magnitude is 16.4 Direction is 156.5°

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A: Given,            v = (-18i + 12j) m/s

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A: We have given,Two forces acting on an object, say F1 = 150 lb  and  F2 = 300 lbWe can resolve both…

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A: This question can be solved using the concept of vectors.

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A: Vector A is <6,-2,-4> Let Vector B i s <23B,-23B,13B> The distance between A  and B  are…

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A: Given that: Magnitude of a→ =24.1mAngle of a→ w.r.t. coordinate axes: θ=68°Angle of primed…

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A: Find the components of vector v. |V| = 9750 θ= 243.0o

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Q: 1. A soccer ball is kicked with a speed of 75 mph at an angle of 30° from the horizontal. Write the…

A: Given query is to find the velocity components.

Q: If a 600-b load is suspended by two chains as shown in the figure to the right. What is the…

A: given  600 lb load is suspended by two chains

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A:

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A: please see the next step for solution

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A: Given :

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A: Given:    20 pounds with 250°      50 pounds with 170°

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A:

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A: 400i+500j-k

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A: To Determine: If v=3i-4j is a velocity vector, express v as a product of its magnitude (its speed)…

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A: We can find the answer as below

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A: Given,           a=7.2 lbs and b=9.7 lbs , θ=110°

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A: REsult :

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A: Answer is provided below

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A: Let the vector be 4i-3j+xk

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A: Unit vector in same direction vectorvector's magnitude

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A: Given, A¯=-5i^+2j^B¯=6i^-5j^

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A: Given that two forces acting on a point P, P1= 30 pounds with N10°E P2=80 pounds with N80°E Now,…