If a ball is thrown straight up into the air with an initial velocity of 40 ft/s, it height in feet after t second is given by y=40t−16t^2. Find the average velocity for the time period beginning when t=2 and lasting (1) 0.1 seconds= ?  (a) 0.01 seconds= ?    (b) 0.001 seconds= ? (c) Finally, based on the above results, guess what the instantaneous velocity of the ball is when t=2?

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