If a woman who is a carrier for Tay-Sachs has children with a man who is not a Tay-Sachs carrier, what is the probability that one of their children will be a carrier for Tay-Sachs? (Sketch a Punnett square to help you find the correct answer.) a. None b. 25% c. 50% d. 75% e. 100%

If a woman who is a carrier for Tay-Sachs has children with a man who is not a Tay-Sachs carrier, what is the probability that one of their children will be a carrier for Tay-Sachs? (Sketch a Punnett square to help you find the correct answer.) a. None b. 25% c. 50% d. 75% e. 100%

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Description: If a woman who is a carrier for Tay-Sachs has children with a man who is not a Tay-Sachs carrier, what is the probability that one of their children will be a carrier for Tay-Sachs? (Sketch a Punnett square to help you find the correct answer.) a.Non

BIOLOGY:CONCEPTS+APPL.(LOOSELEAF)

10th Edition

ISBN:9781305967359

Author:STARR

Publisher:STARR

Chapter14: Human Inheritance

Section: Chapter Questions

Problem 9SA: Alleles for Tay-Sachs disease are inherited in an autosomal recessive pattern. Why would two parents...

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Alleles for Tay-Sachs disease are inherited in an autosomal recessive pattern. Why would two parents with a normal phenotype have a child with Tay-Sachs? a. Both parents are homozygous for a Tay-Sachs allele. b. Both parents are heterozygous for a Tay-Sachs allele. c. New mutations gave rise to Tay-Sachs in the child. d. b or c
Hemochromatosis is an inherited disease caused by a recessive allele. If a woman and her husband, who are both carriers, have three children,what is the probability of each of the following? (a) All three children are of normal phenotype. (b) One or more of the three children have the disease. (c) All three children have the disease. (d) At least one child is phenotypically normal.
A particular person is said to be a carrier of a genetic trait. What does this tell you about their phenotype? (a) They physically show the trait. (b) They physically show the trait more than a noncarrier would show the trait.(c) They are almost normal but show an intermediate phenotype for the trait. (d) They are completely normal and do not physically show the trait.
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Suppose a woman who is a carrier of sickle-cell trait (making her a heterozygote) has children with a man who is totally healthy and does not carry the gene for sickle-cell trait at all. Which one of the following is true about their potential children? (Draw a Punnett square on scratch paper if it helps you.) A) None of their children will have sickle-cell disease. B) All of their children will have sickle-cell disease. C) All of the couple's children would be heterozygous carriers like the mother.
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John and Jane are about to have a child named Jack, John suffers from the rare, autosomal dominant disease called Plant Blindness (8), but is otherwise phenotypically normal. Jane has a different rare, autosomal dominant disease called Disinterest (D) which makes people disinterested in the world around them, but is otherwise phenotypically normal. Disinterest is 60% penetrant A) What is Jane's most likely genotype? B) What is John's most likely genotype? C) What is the probability their offspring, Jack, inherited both conditions and shows the Disinterest phenotype? It has been 20 years, and Jack is about to have a child with another individual Jack turned out to have both Plant Blindness and Disinterest, but his partner in phenotypically normal D. What is the probability Jack's child will inherit both conditions and show the Disintereat phenotype? E) What if B and D were 20 cM apart. Would that change your answer to part D? If so, what is the new probability? Feel free to leave your…
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