If an object is moved a distance D in the direction of an applied constant force F, then the work W done by the force is defined as W= FD If an object is moved along a straight line by a continuously varying force F(x) then the work W done by the force as the object moved from x=a to x=b is W =S" F (x)dx Work as the summation of increments are, AW = force (Distance Increments) = F(Ax) and AW = force Increments (Distance) = F(Ax). Solve with solution: 1. (Lifting chains) A 200-foot chain weighing 5 pounds per foot, is lying coiled on the ground. How much work is required to raise one end of the chain to a height of 20 feet so that it is fully extended.

International Edition---engineering Mechanics: Statics, 4th Edition
4th Edition
ISBN:9781305501607
Author:Andrew Pytel And Jaan Kiusalaas
Publisher:Andrew Pytel And Jaan Kiusalaas
Chapter1: Introduction To Statics
Section: Chapter Questions
Problem 1.12P: A differential equation encountered in the vibration of beams is d4ydx4=2D where x = distance...
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If an object is moved a distance D in the direction of an applied constant force F, then the work W done by the
force is defined as W= FD
If an object is moved along a straight line by a continuously varying force F(x) then the work W done by the
cb
force as the object moved from x=a to x=b is W =[" F (x)dx
a
Work as the summation of increments are,
AW = force (Distance Increments) = F(Ax) and
AW = force Increments (Distance) = F(Ax).
Solve with solution:
1. (Lifting chains) A 200-foot chain weighing 5 pounds per foot, is lying coiled on the ground. How much work is required to
raise one end of the chain to a height of 20 feet so that it is fully extended.
Transcribed Image Text:If an object is moved a distance D in the direction of an applied constant force F, then the work W done by the force is defined as W= FD If an object is moved along a straight line by a continuously varying force F(x) then the work W done by the cb force as the object moved from x=a to x=b is W =[" F (x)dx a Work as the summation of increments are, AW = force (Distance Increments) = F(Ax) and AW = force Increments (Distance) = F(Ax). Solve with solution: 1. (Lifting chains) A 200-foot chain weighing 5 pounds per foot, is lying coiled on the ground. How much work is required to raise one end of the chain to a height of 20 feet so that it is fully extended.
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