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If b1,b2 form an orthonormal basis for C² and x is any vector in C², then |x4 — 2 |x · b₁|²|x · b₂|² - O = |x-b₁4 + x.b₂|4 O|x4|x-b₁|- |x-b₂|* O O O = 0 |x|4 — |x · b₁|² = 2 |x · b₁|²|x · b₂|² + |x · b₂|² None of the given options is correct |x|4 + |x · b₁|¹ − 2 |x · b₁|²|x · b₂|² = |x · b₂|ª

If b1,b2 form an orthonormal basis for C² and x is any vector in C², then |x4 — 2 |x · b₁|²|x · b₂|² - O = |x-b₁4 + x.b₂|4 O|x4|x-b₁|- |x-b₂|* O O O = 0 |x|4 — |x · b₁|² = 2 |x · b₁|²|x · b₂|² + |x · b₂|² None of the given options is correct |x|4 + |x · b₁|¹ − 2 |x · b₁|²|x · b₂|² = |x · b₂|ª

Linear Algebra: A Modern Introduction
Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter5: Orthogonality
Section: Chapter Questions
Problem 20RQ
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If b1, b2 form an orthonormal basis for C? andx is any vector in C2, then O x|4 – 2 |x · b1² |x - b2 = |x · b1|* + |x · b2* |x|4 – x - b1" – |x - be = 0 |x|4 – |x - b1 = 2 |x - b1/* |x - b2 + |x - b2 None of the given options is correct |x|4 + |x · b1 – 2 |x - bị* |x - b2 = |x - bạ| O O O O O
Transcribed Image Text:If b1, b2 form an orthonormal basis for C? andx is any vector in C2, then O x|4 – 2 |x · b1² |x - b2 = |x · b1|* + |x · b2* |x|4 – x - b1" – |x - be = 0 |x|4 – |x - b1 = 2 |x - b1/* |x - b2 + |x - b2 None of the given options is correct |x|4 + |x · b1 – 2 |x - bị* |x - b2 = |x - bạ| O O O O O
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