If ƒ : (0, 1) → R is differentiable and ƒ'(x) ‡ 0 for all x € (0, 1), then there exists at most one c € (0, 1) such that f(c) = 1. Select one: a. False, here is a counter-example: ƒ(x) = x − 1/4. b. False, here is a counter-example: f(x) = x². c. True, by intermediate value theorem. d. True, by Rolle's theorem.
If ƒ : (0, 1) → R is differentiable and ƒ'(x) ‡ 0 for all x € (0, 1), then there exists at most one c € (0, 1) such that f(c) = 1. Select one: a. False, here is a counter-example: ƒ(x) = x − 1/4. b. False, here is a counter-example: f(x) = x². c. True, by intermediate value theorem. d. True, by Rolle's theorem.
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter6: Applications Of The Derivative
Section6.CR: Chapter 6 Review
Problem 1CR
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![If ƒ : (0, 1) → R is differentiable and f'(x) ‡ 0 for all x € (0, 1), then there exists at
most one c € (0, 1) such that ƒ(c) = 1.
Select one:
a.
False, here is a counter-example: ƒ(x) = x − 1/4.
b. False, here is a counter-example: ƒ(x) = x².
c. True, by intermediate value theorem.
O d. True, by Rolle's theorem.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6fe1fc35-672a-49fd-831b-9642c77888ed%2F1266cf06-9623-4f32-af36-547788c1c7db%2Ff3xmm18_processed.png&w=3840&q=75)
Transcribed Image Text:If ƒ : (0, 1) → R is differentiable and f'(x) ‡ 0 for all x € (0, 1), then there exists at
most one c € (0, 1) such that ƒ(c) = 1.
Select one:
a.
False, here is a counter-example: ƒ(x) = x − 1/4.
b. False, here is a counter-example: ƒ(x) = x².
c. True, by intermediate value theorem.
O d. True, by Rolle's theorem.
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