If f(x) = |x|, then f(−1) = 1 and f(3) = 3 but f'(x) is never equal to f(3) − f(−1)/3 − (−1)=1/2. Why doesn’t this violate the Mean Value Theorem?

Q: how do you solve for the critical points of the first derivative of this function? x/4+x^2

A: Differentiating with respect to x, we get

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A:

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A: Topic :- Differentiation

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A:

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A:

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A:

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A:

Q: derivative

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A:

Q: find the critical points and apply the Second Derivative Test (or state that it fails). f(x) = x^2 −…

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A:

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A:

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A:

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A:

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A: To find the derivative of the given function.

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A:

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A:

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A:

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