If K be an extension of a field F then the mapping : F[x]-f(a) defined by (h(x)) = h(a) is Both (A) and (B) Isomorphism Homomorphism O None of the above
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A: Explanation of the answer is as follows
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- Suppose S is a subset of an field F that contains at least two elements and satisfies both of the following conditions: xS and yS imply xyS, and xS and y0S imply xy1S. Prove that S is a field. This S is called a subfield of F. [Type here][Type here]Prove that a polynomial f(x) of positive degree n over the field F has at most n (not necessarily distinct) zeros in F.Suppose that f(x),g(x), and h(x) are polynomials over the field F, each of which has positive degree, and that f(x)=g(x)h(x). Prove that the zeros of f(x) in F consist of the zeros of g(x) in F together with the zeros of h(x) in F.
- Prove Corollary 8.18: A polynomial of positive degree over the field has at most distinct zeros inLet F be a field and f(x)=a0+a1x+...+anxnF[x]. Prove that x1 is a factor of f(x) if and only if a0+a1+...+an=0. Prove that x+1 is a factor of f(x) if and only if a0+a1+...+(1)nan=0.Prove Theorem Suppose is an irreducible polynomial over the field such that divides a product in , then divides some .
- Let be a field. Prove that if is a zero of then is a zero ofTrue or False Label each of the following statements as either true or false. 8. Any polynomial of positive degree that is reducible over a field has at least one zero in .Corollary requires that be a field. Show that each of the following polynomials of positive degree has more than zeros over where is not a field. over over
- Since this section presents a method for constructing a field of quotients for an arbitrary integral domain D, we might ask what happens if D is already a field. As an example, consider the situation when D=5. a. With D=5, write out all the elements of S, sort these elements according to the relation , and then list all the distinct elements of Q. b. Exhibit an isomorphism from D to Q.True or False Label each of the following statements as either true or false. Every polynomial equation of degree over a field can be solved over an extension field of .Prove that any field that contains an intergral domain D must contain a subfield isomorphic to the quotient field Q of D.