If M = {x: Lx = 0}, where L is a continuous linear functional on H, prove that M¹ is a vector space of dimension 1 (unless M = H).

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Q: L-1 15s² (s - 5)³

A: Explanation of the answer is as follows

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Q: okay that makes more sense thank you, but you didn't decompose before taking the laplace inverse, is…

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