if n2 + 10n + n log n = n² + O(n log n). True False Mergesort terminates earlier than Insertionsort for any input. True False Mergesort has an asymptotically better running time than Insertionsort. True False
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- 126. What is the best-case running times for a insertionsort? Group of answer choices linear constant logarithmic polynomial quadraticWrite a program that takes in two positive integer inputs, m and n, and prints out a neatly formatted table of size m * n of all integers between 1 and m in n rows. For example; m = 3, n = 4 1 2 3 1 2 3 1 2 3 1 2 3 Please help me with this problem using c++.Which of the following is/are true about selection sort? Its worst case big-O running time is O( n2) It performs exactly one swap at every pass It performs exactly one comparison at every pass I only II only III only I and II only I, II and III
- Create a programme that receives an integer N from the command line, produces a random BST of size N, then enters a loop that deletes a random key (using the code delete(select(StdRandom.uniform(N))) and then inserts a random key, looping N times. Calculate and show the average length of a path in the tree after the loop (the internal path length divided by N, plus 1). Run your programme for N = 102, 103, and 104 to verify the rather paradoxical claim that this strategy increases the average route length of the tree in proportion to the square root of N.Experiment with a remove() implementation that randomly selects whether to use the previous or successor node.Given two arrays X and Y of positive integers, find the number of pairs such that xy > yx (raised to power of) where x is an element from X and y is an element from Y. Example 1: Input: M = 3, X[] = [2 1 6] N = 2, Y[] = [1 5]Output: 3Explanation: The pairs which follow xy > yx are as such: 21 > 12, 25 > 52 and 61 > 16 .Example 2: Input: M = 4, X[] = [2 3 4 5]N = 3, Y[] = [1 2 3]Output: 5Explanation: The pairs for the given input are 21 > 12 , 31 > 13 , 32 > 23 , 41 > 14 , 51 > 15 . Your Task:This is a function problem. You only need to complete the function countPairs() that takes X, Y, M, N as parameters and returns the total number of pairs. Expected Time Complexity: O((N + M)log(N)).Expected Auxiliary Space: O(1). Constraints:1 ≤ M, N ≤ 1051 ≤ X[i], Y[i] ≤ 103Implement the first round of AES ( Advanced Encryption Standard ) in python. Given a message with 128 bits, two subkeys subkey0 and subkey1, your program should be able to perform one AddKey before Round 1 and the corresponding operations (SubBytes, ShiftRows, Mix-Columns, and AddKey) in Round 1, and output the result of the encryption after Round 1.
- Given two numbers: n: number of consecutive letters beginning at a k: string length Output all possible k-length possible strings containing the first n letters of the alphabet. Letter repeats are allowed. Sample Run: # of letters: 4 length: 3 aaa aab aac aad aba abb abc abd aca acb acc acd ada adb adc add baa bab bac bad bba bbb bbc bbd bca bcb bcc bcd bda bdb bdc bdd caa cab cac cad cba cbb cbc cbd cca ccb ccc ccd cda cdb cdc cdd daa dab dac dad dba dbb dbc dbd dca dcb dcc dcd dda ddb ddc dddYou are given a string X of length n and another string Y of length m ≤n. Say,the indexes p1, p2, p3, p4 and q1, q2, q3, q4 form two sub-sequences, i.e., 0 ≤ p1 < p2 < p3 < p4 < nand 0 ≤q1 < q2 < q3 < q4 < n; then, they are non-overlapping if p4 < q1.The task is to count the maximum number of non-overlapping sub-sequences of X that are thesame as Y . Thus, if X = GAXTYAWBGTAUGBTABGRGTAXB and Y = GTAB, then the answer is3 as shown by the red fonts. We cannot select the underlined GTAB as it overlaps with a red GTAB(i.e., among overlapping sub-sequences, you can select only one of them).Describe an O(m + n) time algorithm to obtain the count. Write a pseudo-code.List pressure_data contains integers read from input, representing data samples from an experiment. Initialize variable sum_passed with 0. Then, for each element in pressure_data that is both at an odd-numbered index and greater than 65: Output 'Index ', followed by the element's index, ': ', and the element's value. Increase sum_passed by each such element's value. # Read input and split input into tokenstokens = input().split() pressure_data = []for token in tokens: pressure_data.append(int(token)) print(f'All data: {pressure_data}') ''' Your code goes here ''' print(f'Sum of selected elements is: {sum_passed}')
- Graph the equations T(n) = log2 n and T(n) = n= loge n. Which gives the better performance, binary search on a sorted list, or sequential search on a list ordered by frequency where the frequency conforms to a Zipf distribution? Characterize the difference in running times.#30 c) What causes InsertionSort to run in its worst-case time complexityO(N^2)?Create a random number generation algorithm using a distribution represented by a finite series of weights.(Wi N for I = 0,... (n 1) 1 n1 i=0 Wi) sequence of n weights W representing the distributionout: Index r was chosen at random in accordance with W (0 r m 1)