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If s(t) = 4t– 6t – 24t + 5, represent the position of a particle traveling along a horizontal line. Determine the time intervals when the object is slowing down or speeding up from the velocity and acceleration functions. O speeding up in (-0,0.5) U (2, 0)and slowing down in (5, o0) speeding up in (-∞,0.5) U (2, 0)and slowing down in (0.5, o0) speeding up in (-0,0.5) U (2, 5)and slowing down in (0.5, 2) speeding up in (-0,0.5) U (2, ) and slowing down in (0.5, 2) O speeding up in (-∞,0.5) n (2, 0)and slowing down in (0.5, 2)

If s(t) = 4t– 6t – 24t + 5, represent the position of a particle traveling along a horizontal line. Determine the time intervals when the object is slowing down or speeding up from the velocity and acceleration functions. O speeding up in (-0,0.5) U (2, 0)and slowing down in (5, o0) speeding up in (-∞,0.5) U (2, 0)and slowing down in (0.5, o0) speeding up in (-0,0.5) U (2, 5)and slowing down in (0.5, 2) speeding up in (-0,0.5) U (2, ) and slowing down in (0.5, 2) O speeding up in (-∞,0.5) n (2, 0)and slowing down in (0.5, 2)

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section: Chapter Questions
Problem 18T
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If s(t) = 4t– 6t - 24t + 5, represent the position of a particle traveling along a horizontal line. Determine the time intervals when the object is slowing down or speeding up from the velocity and acceleration %3D functions. O speeding up in (-o,0.5) U (2, 00)and slowing down in (5, o0) speeding up in (-∞,0.5) U (2, 0)and slowing down in (0.5, o0) speeding up in (-0,0.5) U (2, 5)and slowing down in (0.5, 2) speeding up in (-0,0.5) U (2, 0) and slowing down in (0.5, 2) O speeding up in (-∞,0.5) N (2, 0)and slowing down in (0.5, 2)
Transcribed Image Text:If s(t) = 4t– 6t - 24t + 5, represent the position of a particle traveling along a horizontal line. Determine the time intervals when the object is slowing down or speeding up from the velocity and acceleration %3D functions. O speeding up in (-o,0.5) U (2, 00)and slowing down in (5, o0) speeding up in (-∞,0.5) U (2, 0)and slowing down in (0.5, o0) speeding up in (-0,0.5) U (2, 5)and slowing down in (0.5, 2) speeding up in (-0,0.5) U (2, 0) and slowing down in (0.5, 2) O speeding up in (-∞,0.5) N (2, 0)and slowing down in (0.5, 2)
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