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If the auxiliary roots of a certain homogeneous linear differential equation are 2 + 31, #3i, +31, then the corresponding general solution is y = e* (C, cos 3x + C, sin 3x) + xe²* (C; cos 3x + C, sin 3x) + x²e²* (C; cos 3x + C, sin 3.x) © y = e2*(C, cos 3x + C, sin 3.x) + x²(C; cos 3x + C, sin 3.x) © y=e2* (C, cos 3.x + C2 sin 3.x) + C3, cos 3x + C, sin 3.x +x(C; cos 3x+ C, sin 3x) O y= e2* (C, cos 3x + C, sin 3x) + x(C; cos 3x +C, sin 3.x)+x² (Cs cos 3x + C, sin 3.x)

If the auxiliary roots of a certain homogeneous linear differential equation are 2 + 31, #3i, +31, then the corresponding general solution is y = e* (C, cos 3x + C, sin 3x) + xe²* (C; cos 3x + C, sin 3x) + x²e²* (C; cos 3x + C, sin 3.x) © y = e2*(C, cos 3x + C, sin 3.x) + x²(C; cos 3x + C, sin 3.x) © y=e2* (C, cos 3.x + C2 sin 3.x) + C3, cos 3x + C, sin 3.x +x(C; cos 3x+ C, sin 3x) O y= e2* (C, cos 3x + C, sin 3x) + x(C; cos 3x +C, sin 3.x)+x² (Cs cos 3x + C, sin 3.x)

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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If the auxiliary roots of a certain homogeneous linear differential equation are 2 ± 3i, ±3i, ±3i, then the corresponding general solution is 

If the auxiliary roots of a certain homogeneous linear differential equation are 2= 3i, +3i, +3i then the corresponding general solution is A y = e²* (C, cos 3x + C, sin 3x) + xe²* (C; cos 3.x + C, sin 3x) + x²e²* (C; cos 3x+ C, sin 3x) ® y = e2* (C cos 3x + C, sin 3x) + x²(C; cos 3x + C4 sin 3x) B y = e2* (C, cos 3x+C2 sin 3x)+ C; cos 3x + C, sin 3x + x(C; cos 3x+ C, sin 3x) O y= e2* (C, cos 3.x + C, sin 3x) + x(C; cos 3x+ C, sin 3x)+x² (Cs cos 3x + C, sin 3x)
Transcribed Image Text:If the auxiliary roots of a certain homogeneous linear differential equation are 2= 3i, +3i, +3i then the corresponding general solution is A y = e²* (C, cos 3x + C, sin 3x) + xe²* (C; cos 3.x + C, sin 3x) + x²e²* (C; cos 3x+ C, sin 3x) ® y = e2* (C cos 3x + C, sin 3x) + x²(C; cos 3x + C4 sin 3x) B y = e2* (C, cos 3x+C2 sin 3x)+ C; cos 3x + C, sin 3x + x(C; cos 3x+ C, sin 3x) O y= e2* (C, cos 3.x + C, sin 3x) + x(C; cos 3x+ C, sin 3x)+x² (Cs cos 3x + C, sin 3x)
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