If the braking force ratio of the vehicle that resulted to optimal braking force is 3.46, what is the total max braking force (N) that was developed if the maximum braking force on the rear brakes is 785N?
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- A race car with a 106-inch wheelbase has its weight evenly distributed between front and rear axles. At 150 mi/h, on a race track with = 1.0, the optimal brake force has 67.32% of the braking force on the front brakes. A new racing tire generates = 1.2. At 150 mi/h, what percentage of the braking force should now be allocated to the front to achieve optimal braking?A car weighing 4000 lb is driven down a 5oincline at a speed of 60 mi/h when the brakes are applied, causing a constant total braking force (applied by the road on the tires) of 1500 lb. Determine the distance traveled by the car as it comes to a stop.A 12.5 kN car has a 4000 mm wheelbase, with its center of gravity located 600 mm from the pavement and 1200 mm behind the front axle. Five people weighing on average 80 kg loaded the vehicle, shifting the center of gravity 125 mm nearer to the rear axle. What is the maximum tractive effort (N) that can be developed if the car is a front wheel drive? Use coefficient of road adhesion= 0.55.
- A 12.5 kN car has a 2250 mm wheelbase, with its center of gravity located 550 mm from the pavement and 1150 mm behind the front axle. 3 people weighing on average 95 kg loaded the vehicle, shifting the center of gravity 115 mm nearer to the rear axle. What is the maximum tractive effort (N) that can be developed if the car is a rear wheel drive? Use coefficient of road adhesion= 0.46.A 11120 N car is designed with a 310 cm wheelbase. The center of gravity is located 60 cm above the pavement and 105 cm behind the front axle. If the coefficient of road adhesion is 0.6, what is the maximum tractive effort that can be developed if the car is (a) front-wheel drive and (b) rear-wheel drive?In a certain situation it was estimated that 25% of the braking force was applied to the rear brakes in order for the car to develop the maximum forces required stop the car. If the total braking force developed was 5565 N and the road is wet (u = 0.6), wheelbase of 295 cm and a center of gravity 75 cm above the pavement and 120 cm behind the front axle. Determine the weight of the vehicle (N)
- A 11,455 kN car has a 4,915 mm wheelbase, with its center of gravity located 536 mm from the pavement and 1,226 mm behind the front axle. Five people weighing on average 75 kg each loaded the vehicle, shifting the center of gravity 138 mm nearer to the rear axle. What is the maximum tractive effort (N) that can be developed if the car is a rear wheel drive? Use coefficient of road adhesion=0.55.A 12.52 kN car has a 2.75 m wheelbase, with its center of gravity located 60 cm from the pavement and 115.0 cm behind the front axle. 4 people weighing on average 75 kg loaded the vehicle, shifting the center of gravity 12.0 cm nearer to the rear axle. What is the maximum tractive effort (N) that can be developed if the car is a front wheel drive? Use coefficient of road adhesion = 0.55 .Determine the horsepower produced by a passenger car travelling at a speed of 68 mi/hr on a radius of curvature of 1,200 ft road of 4% grade with a smooth pavement. Assume the weight of the car is 4500 lb and the cross sectional area of the car is 45 ft2.
- In traveling a distance of 3 km between points A and D, a car is driven at 100 km/hr from A to B for t seconds. If the brakes are applied for 4 sec between B and C to give a car uniform deceleration from 100 kmph to 60 kmph and it takes ' t ' seconds to move from C to D with a uniform speed of 60 kmph, determine the value of ' t '.Car 1 is at gasoline station for 10 minutes. The driver notices that car 2 passes at a speed of 40 mph. How long will it take for Car 1 to overtake Car 2 if it accelerated at 4 m/s?The driver of the vehicle on a level road determined that she could increase her speed from rest to 51 kph in 36.80 seconds and from rest to 66 kph in 96.80 seconds. If it can be assumed that the acceleration of the vehicle takes the form:du/dt = α - βutwhere u is the vehicle speed in m/sec. Determine the maximum acceleration of the vehicle