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If the loop has a resistance R which dissipates the energy as heat, what happens to the temperature of the loop as it approaches the current-carrying wire? Please explain clearly

If the loop has a resistance R which dissipates the energy as heat, what happens to the temperature of the loop as it approaches the current-carrying wire? Please explain clearly

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If the loop has a resistance R which dissipates the energy as heat, what happens to the temperature of the loop as it approaches the current-carrying wire? Please explain clearly
A wire along the z-axis (horizontal) with current I going in the positive z-direction produces the magnetic field given by B(x) = -6. μοι 2TS A square loop of side a is initially on top of the wire, with its bottom side positioned at so. The loop is then allowed to freely fall toward the wire IH ☐ I falle down so{ į 2
Transcribed Image Text:A wire along the z-axis (horizontal) with current I going in the positive z-direction produces the magnetic field given by B(x) = -6. μοι 2TS A square loop of side a is initially on top of the wire, with its bottom side positioned at so. The loop is then allowed to freely fall toward the wire IH ☐ I falle down so{ į 2
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