If the original distance is halved to 1 m, what is the force exerted by the two bodies on each other (M1 = M2 = 5 kg)? Compare with the original force. Show calculation and units below: %3D F3 = (1N-m²/kg²)(5 kg)(5 kg)= (1.0 meter)? F3 = F1 %3D %3D By how much has it been increased?
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