If we have six items and four boxes, how many ways are there to arrange them such that no box is left empty?
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If we have six items and four boxes, how many ways are there to arrange them such that no box is left empty?
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- Casinos have devised different automated mechanical methods for shuffling the cards.One such method divides the deck into to seven piles by placing each card randomlyeither on the top or at the bottom of one pile (i.e. each card has 14 possible placesto choose from). After that, the piles are put together to form the shuffled deck.Is this a good method? Can a gambler utilize this information to his advantage?X-Kingdom has trapped n number of soldiers of their opponent. They want to execute them. They created a strategy so that the prisoners will kill each other and at the end one prisoner will be alive and eventually released. As part of the process, they assigned each trapped soldier a sequence number starting from 1 and ending at n. If n = 5 and k = 2, then the safe position is 3. Firstly, the person at position 2 is killed, then person at position 4 is killed, then person at position 1 is killed. Finally, the person at position 5 is killed. So, the person at position 3 survives. If n = 7 and k = 3, then the safe position is 4. The people at positions 3, 6, 2, 7, 5, 1 are killed in order, and the person at position 4 survives. Input:n and k Output:Print the list of prisoners in reverse order from n to 1Then reverse the list to print it in correct order from 1 to nDisplay the position number who will survive. You must have to use circular doubly linked list for your solution.X-Kingdom has trapped n number of soldiers of their opponent. They want to execute them. They created a strategy so that the prisoners will kill each other and at the end one prisoner will be alive and eventually released. As part of the process, they assigned each trapped soldier a sequence number starting from 1 and ending at n. If n = 5 and k = 2, then the safe position is 3. Firstly, the person at position 2 is killed, then person at position 4 is killed, then person at position 1 is killed. Finally, the person at position 5 is killed. So, the person at position 3 survives. If n = 7 and k = 3, then the safe position is 4. The people at positions 3, 6, 2, 7, 5, 1 are killed in order, and the person at position 4 survives. Input:n and k Output:Print the list of prisoners in reverse order from n to 1Then reverse the list to print it in correct order from 1 to nDisplay the position number who will survive. You must have to use circular doubly linked list for your solution. You…
- A hardware store is selling steel rods of various lengths. However, customers sometimes want to buy rods that the store doesn't carry. For example, if the store only carries 10cm and 30cm rods and a customer wants to buy a 25cm rod, then the order cannot be fulfilled. To boost sales, the store has come up with an idea to weld two rods together to make a longer rod. For example, if the store only carries 3cm and 5cm rods and a customer wants to buy a 8cm rod, then the order can be fulfilled by welding together 3-cm and 5-cm rods. Since rod welding can compromise the strength, the store will only weld up to TWO rods together. More precisely, this means, an order for x cm can be fulfilled if there is a single rod of length x or there are two rods (potentially of the same length) whose combined length is x. Your Task: Write a function process Orders (orders: List[int], sizes:List[int]) -> List[bool] to determine whether or not each of the given orders can be fulfilled. Here, orders is a…With T=4, n=12 and A=(3,5,8,8,9,16,29,41,50,63,64,67). Draw the corresponding walkthrough as shown in P.146.There are a set of courses, each of them requiring a set of disjoint time intervals. For example, a course could require the time from 9am to 11am and 2pm to 3pm and 4pm to 5pm. You want to know, given a number K, if it’s possible to take at least K courses. You can only take one course at any single point in time (i.e. any two courses you choose can’t overlap). Show that the problem is NP-complete, which means that choosing courses is indeed a difficult thing in our life. Use a reduction from the Independent set problem.
- In a candy store, there are N different types of candies available and the prices of all the N different types of candies are provided to you. You are now provided with an attractive offer. You can buy a single candy from the store and get at most K other candies ( all are different types ) for free. Now you have to answer two questions. Firstly, you have to find what is the minimum amount of money you have to spend to buy all the N different candies. Secondly, you have to find what is the maximum amount of money you have to spend to buy all the N different candies. In both the cases you must utilize the offer i.e. you buy one candy and get K other candies for free. Example 1: Input: N = 4 K = 2 %3D candies[] = {3 2 1 4} Output: 3 7Imagine there are N teams competing in a tournament, and that each team plays each of the other teams once. If a tournament were to take place, it should be demonstrated (using an example) that every team would lose to at least one other team in the tournament.An n × n square consists of black and white cells arranged in a certain way. The problem is to determine the number of white areas and the number of white cells in each area. For example, a regular 8 × 8 chessboard has 32 one-cell white areas; the square in Figure 5.22a consists of 10 areas, 2 of them of 10 cells, and 8 of 2 cells; the square in Figure 5.22b has 5 white areas of 1, 3, 21, 10, and 2 cells. Write a program that, for a given n × n square, outputs the number of white areas and their sizes. Use an (n + 2) × (n + 2) array with properly marked cells. Two ad- ditional rows and columns constitute a frame of black cells surrounding the entered square to simplify your implementation. For instance, the square in Figure 5.22b is stored as the square in Figure 5.22c. (a–b) Two n 3 n squares of black and white cells and (c) an (n + 2) 3 (n + 2) array implementing square (b). bbbbbbbbbb bwbbwwbwwb bbbbbwbwwb bwwwbbwwwb bwbwbwwbbb bwbwwwbwbb bwbbbbwwwb bwbwbbwwwb bwbwbbwwwb…
- You have a mixed pile of N nuts and N bolts and need to quickly find the corresponding pairs of nuts and bolts. Each nut matches exactly one bolt, and each bolt matches exactly one nut. You can see which is larger by fitting a nut and bolt together, but it is not possible to directly compare two nuts or two bolts.Correct answer will be upvoted else downvoted. Computer science. You and your companions live in n houses. Each house is situated on a 2D plane, in a point with integer organizes. There may be various houses situated in a similar point. The chairman of the city is requesting you for places for the structure from the Eastern show. You need to track down the number of spots (focuses with integer arranges), so the outline distance from every one of the houses to the show is insignificant. The display can be inherent a similar point as some house. The distance between two focuses (x1,y1) and (x2,y2) is |x1−x2|+|y1−y2|, where |x| is the outright worth of x. Input First line contains a solitary integer t (1≤t≤1000) — the number of experiments. The principal line of each experiment contains a solitary integer n (1≤n≤1000). Next n lines portray the places of the houses (xi,yi) (0≤xi,yi≤109). It's reliable that the amount of everything n doesn't surpass 1000. Output For…Suppose, you have been given a non-negative integer which is the height of a ‘house of cards’. To build such a house you at-least require 8 cards. To increase the level (or height) of that house, you would require four sides and a base for each level. Therefore, for the top level, you would require 8 cards and for each of the rest of the levels below you would require 5 extra cards. If you were asked to build level one only, you would require just 8 cards. Of course, the input can be zero; in that case, you do not build a house at all. Complete the recursive method below to calculate the number of cards required to build a ‘house of cards’ of specific height given by the parameter. there is a picture given in that section. public int hocBuilder (int height){ // TO DO } OR def hocBuilder(height): #TO DO