) If X and Y are two independent random variables, then show that: 4/6 Var (X+Y) = Var (X) + Var (Y)

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ISBN:9781337111348
Author:Bruce Crauder, Benny Evans, Alan Noell
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Chapter5: A Survey Of Other Common Functions
Section5.6: Higher-degree Polynomials And Rational Functions
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Q.2 bivarate one 

3016-
-(P-4)(Q-9)(20)
Marks in
Economics
Marks in
Maths
(4)
78 36 98 25 75 82 90 62 65 39
81 51 91 60 68 62 86 58 53 47
(f) Find the least value of r in a sample of 18 pairs of
observations from a bivariate normal population,
significant at 5% level of significance.
(a) There are two bags. The first bag contains 10 white
and 3 black balls and second bag contains 3 white
and 5 black balls. Two balls are drawn at random
5°
from the first bag and put into second bag. Then a
ball is drawn from second bag. Find the 13
probability that the ball drawn is a white ball.
(b) If X and Y are two independent random variables,
then show that:
4/6
Var (X+Y) = Var (X) + Var (Y)
(a) For a random variable X with mean μ = 10 and
variance o² = 4, apply Chebyshev's inequality to
calculate :
-(P-4)(Q-9)(20)
(i) P(5 < X < 15)
(ii) P(|X-10| ≥3)
(iii) P(|X-10| <3)
b) A car hire firm has two cars, which it hires out day
by day. The number of demands for a car on each
day is distributed as a Poisson variate with mean
1.5. Calculate the proportion of days on which :
0.2231
(i) neither car is used
(ii) some demand is refused 1912625
(2)
...
Transcribed Image Text:3016- -(P-4)(Q-9)(20) Marks in Economics Marks in Maths (4) 78 36 98 25 75 82 90 62 65 39 81 51 91 60 68 62 86 58 53 47 (f) Find the least value of r in a sample of 18 pairs of observations from a bivariate normal population, significant at 5% level of significance. (a) There are two bags. The first bag contains 10 white and 3 black balls and second bag contains 3 white and 5 black balls. Two balls are drawn at random 5° from the first bag and put into second bag. Then a ball is drawn from second bag. Find the 13 probability that the ball drawn is a white ball. (b) If X and Y are two independent random variables, then show that: 4/6 Var (X+Y) = Var (X) + Var (Y) (a) For a random variable X with mean μ = 10 and variance o² = 4, apply Chebyshev's inequality to calculate : -(P-4)(Q-9)(20) (i) P(5 < X < 15) (ii) P(|X-10| ≥3) (iii) P(|X-10| <3) b) A car hire firm has two cars, which it hires out day by day. The number of demands for a car on each day is distributed as a Poisson variate with mean 1.5. Calculate the proportion of days on which : 0.2231 (i) neither car is used (ii) some demand is refused 1912625 (2) ...
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