If x is an array of interger, then the value of &x[i] is same as A. &x[i-1] + sizeof (int) B. x + sizeof (int) * i C. x+i D. none of these
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If x is an array of interger, then the value of &x[i] is same as
| A. |
&x[i-1] + sizeof (int) |
| B. |
x + sizeof (int) * i |
| C. |
x+i |
| D. |
none of these |
Step by step
Solved in 2 steps with 1 images
- Write method findZero, as started below. findZero should return the index of the first element of array A that contains the value zero, starting from position 0 up through position pos. If no element of A from position 0 to position pos contains the value zero, then findZero should return –1. For example:(in java) Array (A) Position (pos) Value returned by findZero(A, pos) 1 0 2 5 6 0 -1 1 0 2 5 6 1 1 1 0 2 5 6 2 1 1 0 2 0 6 2 1 1 0 2 0 6 4 1 1 2 3 4 5 4 -1 Complete method findZero below. Assume that it is called only with values that satisfy its assumptions as stated below. // Description: Returns smallest index k // such that (0 <= k <= pos) and (A[k] == 0) // Assumptions: 0 <= pos < A.length public int findZero(int[] A, int pos) {Given an ArrayList of integers, return an ArrayList where all the odds are before the evens in the order that they occur. public ArrayList<Integer> solution(ArrayList<Integer> nums) {ArrayList<Integer> finalList = new ArrayList<>();int index = 0;for (int i = 0; i < nums.size(); i++) {if (nums.get(i) % 2 == 1) {finalList.add(index, nums.get(i));index++;} elsefinalList.add(nums.get(i));}return finalList;} This is my failing code. for [1.-3.3] where [1,3,-3] is being returnedWrite a program that reads an array A of N elements containing only 0's and 1's. Your program should find the position of a 0 and replace it with a 1 to get the longest continuous sequence of 1's. Let this position of 0 be called P. Print P if such a 0 exists and print -1 if the original array A contains only 1's. Assume the array indexing starts from 0.
- Write a program that first reads an integer for the array size, then reads numbers intothe array, and finally outputs how many numbers have values that are greater than theaverage. For practice reasons, try not to use the index notation of arrays (e.g. myarray[i])at all. Use pointers instead.write a java program that implements the insertion sort algorithum that sorts list of doubles in the range of [0,500). use array objects that use to contain the listCall inputLine's split() with "=" as the separator, and assign newArray with the returned array reference. Ex: If the input is bread=butter=cheese=milk, then the output is: bread butter cheese milk Note: str.split(" ") splits string str into an array of strings using a space, " ", as a separator. Ex: If str is "Hello World", then str.split(" ") returns {"Hello", "World"}. 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 import java.util.Scanner; public class CreateArray { publicstaticvoidmain(String[] args) { Scannerscnr=newScanner(System.in); StringinputLine; String[] newArray; inti; inputLine=scnr.nextLine(); /* Your code goes here */ for (i=0; i<newArray.length; ++i) { System.out.println(newArray[i]); } } }
- Write a program in java that randomly fills in 0s and 1s into an n-by-n matrix, prints the matrix, and finds the rows and columns with the most 1s. (Hint: Use two ArrayLists to store the row and column indices with the most 1s.)Write a java program bro find the largest element between first, last, middle value from an array of integers. If the length of array is odd then take the floor valueWrite method findZero, as started below. findZero should return the index of the first element of array A that contains the value zero, starting from position 0 up through position pos. If no element of A from position 0 to position pos contains the value zero, then findZero should return –1. For example: Array (A) Position (pos) Value returned by findZero(A, pos) 1 0 2 5 6 0 -1 1 0 2 5 6 1 1 1 0 2 5 6 2 1 1 0 2 0 6 2 1 1 0 2 0 6 4 1 1 2 3 4 5 4 -1 Complete method findZero below. Assume that it is called only with values that satisfy its assumptions as stated below. // Description: Returns smallest index k // such that (0 <= k <= pos) and (A[k] == 0) // Assumptions: 0 <= pos < A.length public int findZero(int[] A, int pos) {
- Implement a mergeUniqueValues(arr1, arr2) method. When passed two arrays of strings, it will return an array containing the strings that appear in either or both arrays in sorted order. And the returned array should have no duplicates. For example, if you have two string arrays: arr1: {“Bear”, “Elephant”,”Fox”}arr2: {“Panda”, “Elephant”,”Eagle”} Calling mergeUniqueValues(arr1, arr2) should return a merged and sorted array like: Bear, Eagle, Elephant, Fox, Pandacreate a generic array stack and push/pop a million random ints using java.util.Random class. you also want to detect the time it takes to push and pop elements from the stack and you need to run the test multple times to see how the running time grows with increasing number of operations. use a outer loop that runs the program a million times (e.g. for(int i = 1; i<1000000; i+=1000000)).Write a program that will take the sum of the odd-indexed array elements in array of 50 integers completely filled.