If y=sin-t+ tant, xr= - In(-cost)-esinr, find the value of y when +VZe V? -Vzle 2 2/3 V2-e ?

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A: Given:-       To find:- dy/dx

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A: Solving the problem by finding the derivative of the function.

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A: I=∫03sin4xdx Integrating it- I=-cos4x403=-cos124+cos04=1-cos124=0.0054

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A: Antiderivative of sin^2(x) + 2sin(x) is given by,  ∫[ sin2x + 2sinx ]dx =∫sin2x dx + ∫2sinx dx

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A: The solution is given below in the next step:

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Q: 6. Se¯*tane¯*sec?e¬*dx

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Q: 16. S cot xdx /1 + In sin x

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Q: If y = -sin x, what x-value corresponds to a y-value of 1 between 0 and 27? [? ]T

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Q: Sirzy-L652X こつinてy Cos? x CoSz seczK-

A: As per guideline we have to solve the 1st one. For another solution request again

Q: What is the value of the integral S sin(6x) arctan(sin 3x)dx? 2 c) 6 а) 3(т — 2) b) d) 6(т — 2) е) п…

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