igure P7-10. P7-10 Given the partial traverse shown in Figure P7-10 place the following items in the table: ▪ Bearing of each property line (course) ■ Distance of each course ■ Cosine of each bearing angle ■ Sine of each bearing angle ▪ Latitude of each course ■ Departure of each course 262 $50°E 2 0% 6 M.BES 214.8' 253 $70°E 5⁰ N55°W 235' 246' N30°E P

igure P7-10. P7-10 Given the partial traverse shown in Figure P7-10 place the following items in the table: ▪ Bearing of each property line (course) ■ Distance of each course ■ Cosine of each bearing angle ■ Sine of each bearing angle ▪ Latitude of each course ■ Departure of each course 262 $50°E 2 0% 6 M.BES 214.8' 253 $70°E 5⁰ N55°W 235' 246' N30°E P

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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The centerline station of point A is 102+00 and the centerline sta of point B is 135+40. A right of way marker is to be placed 100' black of station 135+40 and 100' left of sta 134+40. What is the straight line distance between the right of way marker and station 135+40? a. 100.0' b. 130.5' c. 141.4' d. 152.3'
A. 283.41mB. 205.12mC. 173.78mD. 195.62mPROVIDE COMPLETE SOLUTION FOR ME TO FOLLOW!
Given the following tabulations are observed and calculated data for a traverse. Balance the latitudes and departures by the COMPASS RULE and compute for the area of the closed traverse by DOUBLE PARALLEL METHOD (DPD). Tip: Before you compute for the area of the closed traverse, you must first adjust the latitudes and departures. LINE DISTANCEAZIMUTH FROM SOUTH LATITUDES(+N) LATITUDES(-S) DEPARTURES(+E) DEPARTURES(-W) AB357.20 m99O45’60.49352.04BC 183.18 154O00’ 164.6480.30CD430.05242O30’198.54381.46DA 425.18 353O15’ 422.2349.97SUMS 423.70 422.23 431.43 432.34
A closed traverse proceeds in a counterclockwise direction and the angle to the right of each station were measuredand recorded as follows. A = 160°19’ ; B = 49°19’ ; C = 115°18’ ; D=127°32’ ; E=88°15’. Calculate for the Error of Closure.https://www.bartleby.com/questions-and-answers/a-closed-traverse-proceeds-in-a-counterclockwise-direction-and-the-angle-to-the-right-of-each-statio/8aecde6f-c077-4f6c-a68a-fc94e35f4d4a
A and B are two points located on each bank of a river and near abutments of a proposed bridge. To determine its distance, a baseline CD 180m long was established on one bank of the river and the transit was set up at stations C and D and the azimuth were taken as follows: Line Azimuth C-D 210°00'; C-A 260°00'; C-B 290°00'; D-A 301 °00'; D-B 315°00' a. Find the distance AD. b. Find the distance BD. c. Find the distance AB.
Answers a) 47.06 kPa b) 78.03 kPa c) 108.30 kPa
F1=113 F2= 181 F3= 508
Answers a) 0.436 b) 17.44 kPa c) 31.98 kPa d) 3.57 kN/m3
What is the elevation at station TP3 A. 127 B. 127.45 C. 123.1 D. 124. 13 E. 124.77
Deflection Angle TraverseThe following are the measured deflection angles for a closed traverse: 97°05’ R,152°18’ R, 96°13’ R, 22°15’ L, and 36°44’ R. Determine the angle error of closurein sexagesimal system of units (° ’ ”). * R = angle to the right, L = angle to the left *** Sum of Deflection Angle = 360° ** Note: EXPRESS YOUR ANSWER UPTO 3 DECIMAL PLACES. (PLEASE PROVIDE A PROVEN AND ACCURATE SOLUTION. THANK YOU.
Choices: a. 712 b. 801 c. 510 d. 902
A closed traverse has the ff. data. What is the bearing of line 5-1? a. S72.07°W b. S76.05°W c. S56.23°E d. S78.31°W