im not understanding how they got 12x10^-15 instead of 2x10^-15 m. for the thickness on part b?

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im not understanding how they got 12x10^-15 instead of 2x10^-15 m. for the thickness on part b? 

Untertainity, frinciple
Ax. Ap=
AP
:-
木/At
: A = 27 (Ax).
the width of the potential uell.
Where An represent
- 15
A = 21 x 12x 10 m
- 14
7.5398 x 10 m
%3D
Transcribed Image Text:Untertainity, frinciple Ax. Ap= AP :- 木/At : A = 27 (Ax). the width of the potential uell. Where An represent - 15 A = 21 x 12x 10 m - 14 7.5398 x 10 m %3D
4. Consider a 1-D head-on collision between a 5-MeV alpha particle and a Be nucleus. As
shown in the figure below, assuming that the Coulomb potential barrier faced by the
alpha particle can be approximated by a single step functions with 2 fm in thickness and
7 MeV in height and that the formula of barrier transmission probability derived from 1-
D Schröedinger equation is valid, calculate: (a) the probability for the alpha partide to
penetrate the Coulomb barrier and enter the Be nucleus, and (b) the de Broglie
wavelength of the alpha particle once it enters the nucleus.
V1 = 7 MeV
5-MeV alpha
particle
Vo = 0 MeV
(i.e. the reference potential outside the Be nucleus)
V2 = - 6 MeV
(i.e. the potential inside the Be nudeus)
Transcribed Image Text:4. Consider a 1-D head-on collision between a 5-MeV alpha particle and a Be nucleus. As shown in the figure below, assuming that the Coulomb potential barrier faced by the alpha particle can be approximated by a single step functions with 2 fm in thickness and 7 MeV in height and that the formula of barrier transmission probability derived from 1- D Schröedinger equation is valid, calculate: (a) the probability for the alpha partide to penetrate the Coulomb barrier and enter the Be nucleus, and (b) the de Broglie wavelength of the alpha particle once it enters the nucleus. V1 = 7 MeV 5-MeV alpha particle Vo = 0 MeV (i.e. the reference potential outside the Be nucleus) V2 = - 6 MeV (i.e. the potential inside the Be nudeus)
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