3- Shaft ABC is composed of two segments: segment AB, which is hollow-core; and segment BC, which is solid. Each end is attached to circular plate, which is fixed to the surroundings via five 8 mm diameter bolts. If the permissible shear stress on the bolts is 150 MPa, what is the maximum allowable value of torque T applied at point B? 16mm End View holes for 8mm bolts or Is this where the It is coming from? hollow-core 0.5m Perspective View Is this where neget the & from? JAB JBC (104)=15708 mm4 (1084)=9274 mmt B T 0 solid Im assuming this is from the somon? Zona for -How do we rane bolt failing in shear P=50.27 (150)=7540N get this Tend=5 Pr=5(7540)20 = 150,800 N·mm (= 150.8 KN-m) value?
3- Shaft ABC is composed of two segments: segment AB, which is hollow-core; and segment BC, which is solid. Each end is attached to circular plate, which is fixed to the surroundings via five 8 mm diameter bolts. If the permissible shear stress on the bolts is 150 MPa, what is the maximum allowable value of torque T applied at point B? 16mm End View holes for 8mm bolts or Is this where the It is coming from? hollow-core 0.5m Perspective View Is this where neget the & from? JAB JBC (104)=15708 mm4 (1084)=9274 mmt B T 0 solid Im assuming this is from the somon? Zona for -How do we rane bolt failing in shear P=50.27 (150)=7540N get this Tend=5 Pr=5(7540)20 = 150,800 N·mm (= 150.8 KN-m) value?
Steel Design (Activate Learning with these NEW titles from Engineering!)
6th Edition
ISBN:9781337094740
Author:Segui, William T.
Publisher:Segui, William T.
Chapter3: Tension Members
Section: Chapter Questions
Problem 3.2.6P
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Please help with what's in red.
Transcribed Image Text:3- Shaft ABC is composed of two segments: segment AB, which
is hollow-core; and segment BC, which is solid. Each end is
attached to circular plate, which is fixed to the surroundings via
five 8 mm diameter bolts. If the permissible shear stress on the
bolts is 150 MPa, what is the maximum allowable value of torque
T applied at point B?
End view
holes for 8mm bolts
Is this where
the It is coming
from?
T
10%
FBD
TAKE
Is this
where
neget the & from?
¹8+)=9274 mmt
JAB
JBC = (10²)=15708 mm4
фавт фес
hollow-core
0.5m
TL
GJ
Perspective View
»T
ET=0:-TA+T+Tc=0
TAB 500
ФАВ=
G9274
$BC = TBC 1000
G15708
Please
add steps
as to how
the final
answer
is found
Is I'm assuming this is from the 20mm?
-How do we
for one bott failing in shear P=50.27 (150)=7540N get this
Tend=5 Pr = 5(7540) 20= 150,800 N·mm (= 150.8 KN-m)
solid
Im
20mm
T=TA
C
TA=0.4585T✔✓ Controls
Tc=-0.5415T
を=T-T
-What happened
TA 500 + (TA-T) 1000 to the B & BC ?
=O
9274
157⁰8
150.8
0.4585 04585 328.9 KN-mm
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Im still confused since we didn't end up with the same final values as the photo. Its showing TA = 0.5415 but in the photo TA is set to 0.4585. Please help me out to understand
Transcribed Image Text:фавт Фес=0
TA 500+ (TA-T) 1000
9274 15708
TA = =
0.4-58sT
Tc=-0.5415T
T=TA
O
✓ controls
150.8
0.4585 04585=3289 KN-mm
=
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