Image one is my code, I wanted to make some change to the blue part's code. The code I written in red(see image 1) is the method to check that an integer has exactly 5 digits is provided for you (fiveDigits). You just need to call it appropriately in your code(the part in blue square)! Notice that the fiveDigits method returns a boolean - think carefully about how you should use this return type to reprompt the user until they enter a valid zip code. And I want the same output be like (see image 2)
Image one is my code, I wanted to make some change to the blue part's code.
The code I written in red(see image 1) is the method to check that an integer has exactly 5 digits is provided for you (fiveDigits). You just need to call it appropriately in your code(the part in blue square)! Notice that the fiveDigits method returns a boolean - think carefully about how you should use this return type to reprompt the user until they enter a valid zip code.
And I want the same output be like (see image 2)
for the invalid zip code part: I should only reprompt the user with the message "Invalid zip-code, enter valid zip-code: " until they enter a valid zip code. Similarly, if the user enters an invalid pain level, you should reprompt the user with the message "Invalid pain level, enter valid pain level (1-10): " until they enter a valid pain level. For example（image2)
![1- import java.util.*;
2 public class Main
3- {
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}
public static void main(String[] args)
{
}
System.out.println("Hello! We value you and your time, so we will help\nyou prioritize which patients to see next!\nPlease answer the following questions about the next patient so\nwe can help you do
String name = "";
Scanner sc = new Scanner(System.in);
while (!name.equals("quit"))
{
}
System.out.print("Patient's name: ");
name = sc.next();
if(name.equals("quit"))
System.out.print("Patient's age: ");
int age sc.nextInt ();
System.out.print("Patient's zip code: ");
int zip sc.nextInt();
break;
while(String.valueof(zip).length() != 5)
System.out.print("Invalid zip code, enter valid zip code: ");
zip sc.nextInt ();
if(String.valueOf(zip).length() == 5)
}
System.out.print("Is our hospital \"in network\" for the patient's insurance? ");
String insurance sc.next();
{
break;
System.out.print("Patient pain level (1-10): ");
int pain sc.nextInt ();
while(pain < 1 || pain > 10)
System.out.print("Invalid pain level, enter valid pain level (1-10): ");
pain sc.nextInt ();
}
if (pain >= 1 && pain <= 10)
break;
System.out.print("Patient temperature (in degrees Fahrenheit): ");
double temperature sc.nextDouble();
public static boolean five Digits (int val) {
val= val / 10000;
if (val == 0) {
:
return false;
} else if (val / 10 == 0) {
return true
} else {
return false;](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6c680976-d041-43f6-b2b7-59630778639d%2Ff141bbcc-3347-499e-9dc4-a0e1a203658e%2Fc7fs8jl_processed.jpeg&w=3840&q=75)
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But for the name == quit, you are still using the break, can you also change that one too?
by Bartleby ExpertWe can't use "break" in this code, can you change to other ways to do it?
(maybe use if or if else or if else if)
plz provide a screenshot of the code and out put .
Thanks
by Bartleby ExpertThank you, but we don't allowed to use the "break", is there any other way to do it? (Maybe use if or else if)?
also plz provide a screenshot of the code and output.
by Bartleby Expert
