In a communication, the transmitted data is 01110101011 and the received data is 00 1110100011. For error detection, 2D Parity algorithm is used with (3 row and 4 column). Which answer is correct? O a. Error-can be detected and corrected O b. Error is only detected by row, but cannot be corrected Oc Error is only detected by column, but cannot be corrected O d. Error cannot be detected Oe. Error is detected by row and column, but cannot be corrected
Q: The message received at the receiver end is 1011011. Assuming even parity from left to right, state…
A: The answer is
Q: The message received at the receiver end is 1011011. Assuming even parity from left to right, state…
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Q: The sender sends the following message 00111001011 to the receiver. Using the vertical redundancy…
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- A sender needs to send the two data items 110001 and 100110, find the checksum atsender and receiver to check if there is any error or not?Suppose the sender and the receiver agree to use the bit pattern 01111110 to mark the beginning and the end of a frame. 1)The sender has the following bits to send. What does the sender actually send? 011110000111111011101111101 2) The receiver receives the following bits. What're the original data bits (note: this question has nothing to do with the previous question) 01111110111110111110001101111101000011111001111110A sender needs to send the four data items Ox3456, OxABCC, Ox02BC, and OxEEEE.Answer the following:a. Find the checksum at the sender site.b. Find the checksum at the receiver site if there is no error.c. Find the checksum at the receiver site if the second data item is changed to OxABCE.d. Find the checksum at the receiver site if the second data item is changed to OxABCE and the third data item is changed to Ox02BA.
- A sender transmits a message: 11001010; the data received by the receiver is 11010000. Using vertical redundancy check with even parity, (1) does the receiver interpret the message with error or with no error? (2) Is the error checker correct or incorrect?a. Compute CBC-MAC for a message of 16 bits, “8642” (in Hexa). Assume a block size of 8 bits with an IV=F1 (in hexa). For simplicity, assume the encryption to be a simple XOR of the key with the plaintext. Let the encryption key be B4 (in Hexa). (Hint: Divide the message into blocks of 8 bits each; XOR each block with the previous cipher output; then encrypt this with the key. For the first block, XOR it with IV. Details in pages 325-326 Ch.12 of the textbook) b. Suppose Alice computes the Secret prefix MAC (page 322: secret prefix MAC(x) = h(key || x)) for the message ”AM” (in ASCII) with key “G” (in ASCII) that both Alice and Bob know. The hash function that is used is h(x1x2x3)= g(g(x1 XOR x2) XOR x3 ) where each xi is a character represented as 8 bits, and g(x) is a 8-bit string that is equal to the complement of bits in x. For example, g(10110011) = 01001100. The MAC is 8 bits. (8-bit ASCII representation of the characters is given below.) What is the Secret prefix MAC…ACTIVITY : CODING Suppose the following messages are source encoded given by the table. Message Encoded Bits UP 00 DOWN 01 LEFT 10 RIGHT 11 Complete the given table by writing the source encoded message of the following set of directions. Set of Directions Source Encoding LEFT - UP - RIGHT - DOWN 1.) 10001101 UP - DOWN - UP - RIGHT 2.)00010011 DOWN - DOWN - RIGHT - LEFT 3.) 01011110 UP - DOWN - LEFT - RIGHT 4.)00011011 RIGHT - LEFT - RIGHT - UP 5.)11101100 Decode the set of directions given by the message received. Message Received Decoded Message 10010011 1.) 01010010 2.) 11000110 3.) 01100111 4.) 00101111 5.) III. Complete the given table by writing the channel encoded message by using parity check of adding 1 bit in the message. Message Source Encoding Channel Encoding ALLY 000 1.) ENEMY 011 2.) ATTACK 100 3.) RETREAT…
- The sender sends the following message 11011000011 to the receiver. Using Vertical Redundancy Check, which of the following will be detected as having an error and rejected using an even number of 1s?A sender sends binary data 101011111001110. The checksum has eight bits length, what is the checksum that should be sent?Computer Network : Suppose 3 blocks of 16 bits need to be sent, using Checksum method proves the following cases: When there is no error When there is a burst error and detected. When there is a burst error and remains undetected Block 1: 1011101110101011 Block 2: 0101000011111010 Block 3: 0111010110101010
- 4-The following block is sent: 0110111 0101010 1101010 1010101. Using a 2-dimensional parity check, what will be received by the receiver without the block being corrupted in transmission. put a space after each frame (8 bits). your final answer shoule be 5 frames. 5-Given: Original message : 110101010; Generator: 1010 Perform a CRC Calculation: 6-The symbols M and N are transmitted. Show the transmission of this data (at the sender and receiver) using Checksum Method.Show all the steps to find value of CRC for dataword 10110101 and the divisor (polynomial value) is 10011. What is the value of CRC? What is binary value of Codeword that will be sent on the network Show all the steps to determine if there is any error in the received code word: 101101010100 where the divisor is 10011A sender needs to send the four data items 0x1236, 0xABCC, 0x03BC, and 0xEEEE. To avoid confusion, 0x is written in the prefix to denote that the data is in Hexadecimal. For example, 0x3456 is 3456 in hexadecimal. Now answer the following: i. Find the checksum at the sender site. ii. Find the checksum at the receiver site if there is no error. iii. Find the checksum at the receiver site if the second data item is changed to 0xABCE and the third data item is changed to 0x02BA.