In a gradually varied flow in the channel, the depth of flow and the critical depth is y and ye respectively. If E is the specific energy and d is positive, then E would be: dr d.r
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Q: critical depth of flow in m
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- The difference in the water surface of the two reservoirs is 9m. The reservoirs are connected by a siphon of length 1000m and 0.2m diameter. The summit of the pipe is 3m above the water surface level of upper reservoir. The length of pipe from upper reservoir to the summit is 200m. Determine the discharge through the siphon and also the pressure at the summit. Take friction factor as 0.02 and neglect all minor losses.Water flows at 2 m / s in a 3 m wide 2.5 m deep rectangular channel. There is a 1.10 m elevation on the downstream side of the channel as seen in the figure. Above the elevation, the channel widens to 3.75 m as shown in the figure If b2 = 3.75 m, what should be the maximum value of Δz to prevent suffocation? Draw the specific energy depth curve.which of the following mostly depends on headloss? a. pressure headb. elevation headc. velocity head in uniformly sized pipe, which of the following is constant? a. pressure headb. elevation headc. velocity head in compressible flow, which is mostly conserved among the following variables? a. densityb. volumec. mass
- The water tank is below a constant level at depth h rectangular hole a x b. We close the opening with an immersion wall from the upper edge of the hole by a distance x. Given: h = 0.85 m, a = 0.4 m, b = 0.7 m. Determine: by what distance x do we have to move the immersion wall, to reduce the flow 3 times, what will be the flow Q1 at submerged wall by x, Reynolds number Re in flow, nature of flow.Two reservoirs are connected by a pipeline which is 150 mm in diameter for the first 6 m and 225 mm in diameter for the remaining 18 m. The entrance and exit are sharp, and the change of section is sudden. The water surface in the upper reservoir is 6 m above that in the lower. Tabulate the losses of head which occur and calculate the rate of flow in m3/s. Friction coefficient f is 0.01 for both pipes.Two reservoirs, A and B, are 7.5 km away from each other and connected by a 900 mm steel pipe ( f = 0.02). If reservoir A is 10 m higher than reservoir B, the pressure at B is 90 kPa greater that the pressure at reservoir A, what is the amount and direction of flow of water in the pipe. Use f = 0.02.
- a siphon with its upper end immersed in a large reservoir of oil (s.g. 0.80). The pipe is 6 in in diameter. Compute the discharge and the pressure at point 2, if the loss of head from 1 to 2 is 5 ft and from 2 to 3 is 8 ft.A water reservoir of 300 (Height) x 300 (width) x 500 (depth) m has its free surface at 250 m above a bottom outlet orifice of 500 mm in diameter. The velocity coefficient of the orifice is 0.96 and the coefficient of contraction of the flow through the orifice is 0.6. Assume that the reservoir has a cubic shape. Q1. Calculate the velcoity of water in the reservoir when it starts to empty (m/s)For a wide open rectangular channel, if the critical velocity is 6 m/s, 1. What is the critical depth, in m. 2. Compute the minimum specific energy, in m. 3. Determine the critical flow if the width of the channel is 3 m, in m3 /s Solve all parts and correct answer
- Fill in the blanks. (Hydraulics) 1) The most efficient cross section of an open channel, given the slope, area and roughness coefficient, is that which yields the ___ wetted perimeter for a given cross-section, thereby having the maximum capacity. 2) The channel lining (side and base of the channel) which comes in direct contact with the liquid stream is called ___.Total head (energy) is constant along a pipe system and is 25 m. At Point B, the flow rate is 1.2 m3/s where the rectangular pipe has a height of .5 m and a width of .4 m. What is the static head at Point B, in m?An inverted right circular conical tank loses water out of a 4-in hole at the bottom. The radius of the top of the tank is 8 ft and its total height is 20 ft. Assume that the coefficient of contraction is 0.6. Solve for dh/dt. Solve for dV/dt.