In a health examination survey of a prefecture in Japan, the population was found to have anaverage fasting blood glucose level of 99.0 with a standard deviation of 12 (normallydistributed). What is the probability that an individual selected at random will have a bloodsugar level readıng between 90 & 111?O 0.7641O 0.6147O 0.5888O None of the other options'

Given that Mean =99 ,s.d =12 Find p ( 90 < x <111 ) = ?

In a health examination survey of a prefecture in Japan, the population was found to have an average fasting blood glucose level of 99.0 with a standard deviation of 12 (normally distributed). WVhat is the probability that an individual selected at random will have a blood sugar level reading between 90 & 111? 0.7641 0.6147 O 0.5888 None of the other options

In a health examination survey of a prefecture in Japan, the population was found to have an average fasting blood glucose level of 99.0 with a standard deviation of 12 (normally distributed). WVhat is the probability that an individual selected at random will have a blood sugar level reading between 90 & 111? 0.7641 0.6147 O 0.5888 None of the other options

College Algebra

10th Edition

ISBN:9781337282291

Author:Ron Larson

Publisher:Ron Larson

Chapter8: Sequences, Series,and Probability

Section8.7: Probability

Problem 11ECP: A manufacturer has determined that a machine averages one faulty unit for every 500 it produces....

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