In a period of 9.00 s, 5.00 × 1023 nitrogen molecules strike a wall of area 5.80 cm². Assume the molecules move with a speed of 340 m/s and strike the wall head-on in elastic collisions. What is the-26 kg.pressure exerted on the wall? Note: The mass of one N, molecule is 4.65 x 103.513Calculate the momentum change in each second and use the impulse-momentum theorem to relate the momentum change to the average force between the wall and the nitrogen in order to find thepressure. kPaNeed Help?Read ItMaster It

Solution:-Given thattime (∆t)=9 sNumber of molecules (N)=5×1023Area (A)=5.8 cm2=5.8×10-4 m2Initial…

In a period of 9.00 s, 5.00 x 1023 nitrogen molecules strike a wall of area 5.80 cm. Assume the molecules move with a speed of 340 m/s and strike the wall head-on in elastic collisions. What is the pressure exerted on the wall? Note: The mass of one N, molecule is 4.65 x 10-26 kg. 3.513 x Calculate the momentum change in each second and use the impulse-momentum theorem to relate the momentum change to the average force between the wall and the nitrogen in order to find the pressure. kPa Need Help? Master It Read It

In a period of 9.00 s, 5.00 x 1023 nitrogen molecules strike a wall of area 5.80 cm. Assume the molecules move with a speed of 340 m/s and strike the wall head-on in elastic collisions. What is the pressure exerted on the wall? Note: The mass of one N, molecule is 4.65 x 10-26 kg. 3.513 x Calculate the momentum change in each second and use the impulse-momentum theorem to relate the momentum change to the average force between the wall and the nitrogen in order to find the pressure. kPa Need Help? Master It Read It