In a simple hydraulic system piston 1 has a cross-section area of 0.000050 m², and piston 2 has a cross-section area of 0.00025. If a force of 35 N is applied to piston 1, What is the force-multiplying ratio?

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In a simple hydraulic system piston 1 has a
cross-section area of 0.000050 m², and
piston 2 has a cross-section area of
0.00025.
If a force of 35 N is applied to piston 1,
What is the force-multiplying ratio?
Transcribed Image Text:In a simple hydraulic system piston 1 has a cross-section area of 0.000050 m², and piston 2 has a cross-section area of 0.00025. If a force of 35 N is applied to piston 1, What is the force-multiplying ratio?
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