In a survey of women in a certain country (ages 20-29), the mean height was 64.8 inches with a standard deviation of 2.72 inches. Answer the following questions about the specified normal distribution (a) What height represents the 95th percentile? (b) What height represents the frst quartie? Click to view Dage 1 of the table. Click to view paon 2of the table (a) The height that represents the 95th percentile is inches (Round to two decimal places as needed) (b) The height that represents the frst quartie isinches. (Round to two decimal places as needed)

Q: In a survey of women in a certain country (ages 20-29), the mean height was 64.9 inches with a…

A: Given that  The mean height of a women =64.9 inches  Standard deviation =2.89 Then we have to find…

Q: In a survey of women in a certain country​ (ages 20−​29), the mean height was 63.8 inches with a…

A: Solution: Let X be the height. From the given information, X follows normal distribution with mean…

Q: In a survey of women in a certain country (ages 20 - 29), the mean height was 62.9 inches with a…

A:

Q: In a survey of women in a certain country​ (ages 20-29), the mean height was 64.4 inches with a…

A: The quartile is a term used in statistics that divides the statistical observation into 4 divisions.…

Q: In a survey of women in a certain country​ (ages 20−​29), the mean height was 66.9 inches with a…

A:

Q: In a survey of women in a certain country (ages 20 - 29), the mean height was 62.6 inches with (a)…

A:

Q: In a survey of women in a certain country​ (ages 20−​29), the mean height was 64.5 inches with a…

A: Let us denote X= height of women Given that X follows a normal distribution with mean= 64.5 and…

Q: In a symmetric bell-shaped distribution, about what percent of ? values lie between the first and…

A: According to the empirical rule, in a symmetric bell shaped distribution about 68.3% of the values…

Q: In a survey of women in a certain country​ (ages 20−​29), the mean height was 65.2 inches with a…

A:

Q: In a survey of women in a certain country​ (ages 20−​29), the mean height was 65.4 inches with a…

A: Given that, μ=65.4 inches and σ=2.78 inches (a) The height represents the 95th ​percentile is,…

Q: In a survey of women in a certain country (ages 20- 29), the mean height was 63.4 inches with a…

A: GivenMean = 63.4 inchesStandard deviation = 2.87 inches The Z score for 95th percentile is 1.645

Q: In a survey of a group of men, the heights in the 20-29 age group were normally distributed, with a…

A: To determine: To determine how may would you expect to be taller than 71 inches . Given data: In a…

Q: In a survey of women in a certain country (ages 20-29), the mean height was 65.6 inches with a…

A: (b)The first quartile is euql to 25th percentail.The height represents the first quartile is 63.66,…

Q: In a survey of women in a certain country (ages 20 - 29), the mean height was 66.5 inches with a…

A: a) The Z-score of a random variable X is defined as follows: Z = (X – µ)/σ. Here, µ and σ are the…

Q: survey of women in a certain country​ (ages 20−​29), the mean height was 66.4 inches with a standard…

A:

Q: In a survey of women in a certain country (ages 20 - 29), the mean height was 62 9 inches with a…

A: Given Data : Population Mean,μ = 62.9 Population Standard Deviation,σ = 2.71

Q: (a) What height represents the 95th ​percentile? ​(b) What height represents the first​ quartile?

A: (a) The random variable X is defined as the height of women which follows normal distribution with…

Q: In a survey of women in a certain country​ (ages 20−​29), the mean height was 65.9 inches with a…

A: GivenMean(μ)=65.9standard deviation(σ)=2.66

Q: The number of chocolate chips in an 18-ounce bag of chocolate chip cookies is approximately normally…

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Q: In a survey of women in a certain country (ages 20 – 29), the mean height was 62.9 inches with a…

A: It is given that the mean height is 62.9 inches and standard deviation is 2.66 inches.

Q: Rashid is 84 inches tall. If the height of males in the United States is nor- mally distributed with…

A: Height of Rashid = x = 84 inches. Mean =  70 Standard deviation = 4 The z-score is given by z-score…

Q: Heights of 10 year olds, regardless of gender, closely follow a normal distribution with mean 55…

A:

Q: n a survey of women in a certain country​ (ages 20−​29), the mean height was 62.9 inches with a…

A: (a) Obtain the height that represents the 95thpercentile. The height that represents the…

Q: In a survey of women in a certain country​ (ages 20−​29), the mean height was 62.7 inches with a…

A: Mean height of women (μ)= 62.7, Standard deviation of women's height (σ) = 2.66.

Q: In a survey of women in a certain country​ (ages 20−​29), the mean height was 63.7 inches with a…

A:

Q: A physical fitness association is including the mile run in its secondary-school fitness test. The…

A: P(X<348)=?

Q: 2) The height of women in the United States fits a normal distribution with a mean height of 64.5…

A: using:- The table below shows Z values for commonly used percentiles.   Percentile Z 1st…

Q: The students of a large university in Luzon were studied regarding their hours of sleep at night.…

A: As the distribution of the hours of sleep can be modeled as normal distribution with mean μ of 6.9…

Q: In a survey of women in a certain country (ages 20 - 29), the mean height was 63.2 inches with a…

A: The height is normally distributed with mean 63.2 inches and standard deviation 2.69. Define the…

Q: In a recent study, the serum cholesterol levels in men were found to be normally distributed with a…

A: Consider that the mean and standard deviation of a random variable X are µ and σ, respectively.…

Q: In a survey of women in a certain country​ (ages 20−​29), the mean height was 65.4 inches with a…

A: GivenMean(μ)=65.4standard deviation(σ)=2.81

Q: In a survey of women in a certain country​ (ages 20−​29), the mean height was 65.7 inches with a…

A:

Q: In a survey of women in a certain country​ (ages 20−​29), the mean height was 65.3 inches with a…

A: Given Data: Let X represent the random variable   Mean=65.3 SD=2.85   X~ Normal (65.3, 2.852)

Q: Dole Pineapple Inc. is concerned that the 16-ounce can of sliced pineapple is being overfilled.…

A: Since you have posted a question with multiple sub-parts, we will solve first three sub-parts for…

Q: According to a marketing website, adults in a certain country average 51 minutes per day on mobile…

A: We are given,Mean = μ = 51Standard deviation = σ = 7Percentile = 80th

Q: In a survey of women in a certain country​ (ages 20−​29), the mean height was 64.8 inches with a…

A:

Q: The amount of corn chips dispensed into a 20-ounce bag by the dispensing machine has been identified…

A:

Q: In a survey of women in Canada, the mean height was 65 inches with a standard deviation of 3 inches.…

A:

Q: In a survey of women in a certain country​ (ages 20−​29), the mean height was 65.2 inches with a…

A: From the provided information, Mean (µ) = 65.2 inches Standard deviation (σ) = 2.68 inches X~N…

Q: (AKS 24): A technology magazine finds data that suggests the prices of computers with a specific…

A:

Q: In a survey of women in a certain country​ (ages 20−​29), the mean height was 66.8 inches with a…

A: (a) Obtain the height that represents the 95th percentile. The height that represents the 95th…

Q: In a survey of women in a certain country​ (ages 20−​29), the mean height was 63.8 inches with a…

A: Given that,  In a survey of women in a certain country (ages 20 -29), the mean height was 64.7…

Q: In a survey of women in a certain country (ages 20 - 29), the mean height was 63.3 inches with a…

A: GivenMean = 63.3 inchesStandard deviation = 2.84 inches The Z score for 95th percentile is 1.645 The…

Q: Heights of 10 yr Olds, regardless of gender, follow normal distribution with mean 55 inches and…

A: Given information- We have given the heights of 10 yr Olds, regardless of gender, follow the normal…

Q: In a normal distribution with a mean of 72 and a standard deviation of 12, what percentage of…

A:

Q: The ages of the employees at Solar Systems, Inc. is normally distributed with a mean of 32.7 years…

A: Let X=ages of the employees at Solar Systems, Inc. Given that X follows normal distribution with…

Q: In a survey of women in a certain country (ages 20-29), the mean height was 63.6 inches with a…

A: GivenMean(μ)=63.6standard deviation(σ)=2.75

Q: What height represents the 95th ​percentile? ​(b) What height represents the first​ quartile?

A: Here Given  For survey of women in certain country for their height Mean=μ=66.6 Inches SD=σ=2.72…

Q: In a survey of women in a certain country (ages 20- 29), the mean height was 66.1 inches with a…

A: Given that, μ=66.1 inchesσ=2.74 inches (a) The height represents the 95th percentile is,

Q: In a survey of women in a certain country (ages 20 - 29), the mean height was 62.5 inches with a…

A: Givenμ=62σ=2.68

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.