In AMNP and AQRT, NP = RT, MN = QR, and ZN = LR. Can AMNP anAQRT be proven congruent? If so, which triangle shortcut is used?NOYes, by SASYes, by SSAYes, by SAS-Yes, by HLEvaluate: (Scroll Down to see all options) *110. Given: ANEW = ACARAR = 4y – 12CA = 4x + 3NE = 11NW = x +yEW = 10Solve for x, y and CR.CR = 5/2CR = 15/2CR = 25/2CR = 35/2

SAS (Side-Angle-Side) If any two sides and the angle included between the sides of one triangle are…

Answered: In AMNP and AQRT, NP = RT, MN = QR, and…

In AMNP and AQRT, NP = RT, MN = QR, and ZN = LR. Can AMNP an AQRT be proven congruent? If so, which triangle shortcut is used? NO Yes, by SAS Yes, by SSA Yes, by SAS- Yes, by HL

Elementary Geometry For College Students, 7e

7th Edition

ISBN:9781337614085

Author:Alexander, Daniel C.; Koeberlein, Geralyn M.

Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.

Chapter3: Triangles

Section3.2: Corresponding Parts Of Congruent Triangles

Problem 44E: HA hypotenuse-angle is also a valid method for proving that two right triangles are congruent a...

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Question

In AMNP and AQRT, NP = RT, MN = QR, and ZN = LR. Can AMNP an
AQRT be proven congruent? If so, which triangle shortcut is used?
NO
Yes, by SAS
Yes, by SSA
Yes, by SAS-
Yes, by HL
Evaluate: (Scroll Down to see all options) *
1
10. Given: ANEW = ACAR
AR = 4y – 12
CA = 4x + 3
NE = 11
NW = x +y
EW = 10
Solve for x, y and CR.
CR = 5/2
CR = 15/2
CR = 25/2
CR = 35/2

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