In cylindrical coordinates, a vector function of position is given by f = r² zer +4r²e + 2zęz Consider the region of space bounded by a cylinder of radius 2 centered around the z-axis, and having faces at z = -1 and z=1. a) Compute the value of ſf (f.n) dA by direct computation of the surface integral. b) Explain on physical grounds why the component of ƒ in the direction does not contribute to the surface integral. c) Determine the value of ſſf (V.ƒ)dV by direct computation of the volume integral.
In cylindrical coordinates, a vector function of position is given by f = r² zer +4r²e + 2zęz Consider the region of space bounded by a cylinder of radius 2 centered around the z-axis, and having faces at z = -1 and z=1. a) Compute the value of ſf (f.n) dA by direct computation of the surface integral. b) Explain on physical grounds why the component of ƒ in the direction does not contribute to the surface integral. c) Determine the value of ſſf (V.ƒ)dV by direct computation of the volume integral.
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![In cylindrical coordinates, a vector function of position is given by
f = r²zer + 4r²e + 2zęz
Consider the region of space bounded by a cylinder of radius 2 centered around the z-axis, and
having faces at z = -1 and z=1.
a) Compute the value of ff (f.n) dA by direct computation of the surface integral.
A
b) Explain on physical grounds why the component of f in the direction does not
contribute to the surface integral.
c) Determine the value of fff (V. f)dV by direct computation of the volume integral.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0c361b92-5ba5-4cb8-be48-855fd5894535%2F3e77dd34-987e-4e5c-95c3-eccb0d27ff15%2Fjfzb0ve_processed.jpeg&w=3840&q=75)
Transcribed Image Text:In cylindrical coordinates, a vector function of position is given by
f = r²zer + 4r²e + 2zęz
Consider the region of space bounded by a cylinder of radius 2 centered around the z-axis, and
having faces at z = -1 and z=1.
a) Compute the value of ff (f.n) dA by direct computation of the surface integral.
A
b) Explain on physical grounds why the component of f in the direction does not
contribute to the surface integral.
c) Determine the value of fff (V. f)dV by direct computation of the volume integral.
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