In Drosophila, the allele for brown eyes (b) is recessive, while the red eye allele (B) is dominant. How would you set up a two gene test cross to determine the genotype of a male who has a normal body colour and red eyes? List all of the possible genotypes for the male Drosophila:. 50% of the resulting progeny are yellow-brown bodies with red eyes, and 50% have ebony bodies with red eyes. (a) What Is the genotype of the male Drosophila? (b) Explain your answer:

In Drosophila, the allele for brown eyes (b) is recessive, while the red eye allele (B) is dominant. How would you set up a two gene test cross to determine the genotype of a male who has a normal body colour and red eyes? List all of the possible genotypes for the male Drosophila:. 50% of the resulting progeny are yellow-brown bodies with red eyes, and 50% have ebony bodies with red eyes. (a) What Is the genotype of the male Drosophila? (b) Explain your answer:

Name: In Drosophila, the allele for brown eyes (b) is recessive, whlle the
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Description: In Drosophila, the allele for brown eyes (b) is recessive, whlle the red eye allele (B) is dominant. How would you set upa two gene test cross to determine the genotype of a male who has a normal body colour and red eyes?List all of the possible gen

Concepts of Biology

1st Edition

ISBN:9781938168116

Author:Samantha Fowler, Rebecca Roush, James Wise

Publisher:Samantha Fowler, Rebecca Roush, James Wise

Chapter8: Patterns Of Inheritance

Section: Chapter Questions

Problem 2ACQ: Figure 8.10 In pea plants, purple flowers (P) are dominant to white (p), and yellow peas (Y) are...

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In Drosophila, a cross was made between a yellowbodied male with vestigial (not fully developed)wings and a wild-type female (brown body). The F1generation consisted of wild-type males and wild-typefemales. F1 males and females were crossed, and theF2 progeny consisted of 16 yellow-bodied males withvestigial wings, 48 yellow-bodied males with normalwings, 15 males with brown bodies and vestigialwings, 49 wild-type males, 31 brown-bodied femaleswith vestigial wings, and 97 wild-type females.Explain the inheritance of the two genes in questionbased on these results.
You carry out a trihybrid cross (a cross in which the parental plants differ for three characters) between a tall pea plant with round, yellow seeds (TT RR YY) and a short pea plant with wrinkled, green seeds (tt rr yy). The parental plants are homozygous for all of the three characters. They are crossed to produce the F1 generation. Tall, round, and yellow are the dominant traits for each character. What will be the phenotypes of the F1 generation?
Three genes in fruit flies affect a particular trait, and at least one dominant allele of each gene is necessary to get a wild-type phenotype. a. What phenotypic ratio would you predict among the progeny if you crossed triply heterozygous flies? b. You cross a particular wild-type male in succession with three tester strains. In the cross with one tester strain (AA bb cc), only 1/4 of the progeny are wild type. In the crosses involving the other two tester strains (aa BB cc and aa bb CC), half of the progeny are wild type. What is the genotype of the wild-type male? (Pls help asap!!)
Red eyes is the wild-type phenotype in Drosophila, and severaldifferent genes (with each gene existing in two or more alleles) affect eye color. One allele causes purple eyes, and a different allelecauses vermilion eyes. The purple and vermilion alleles are recessive to red eye color. Two types of crosses provided thefollowing data:Cross 1: Males with vermilion eyes × females with purple eyes354 offspring, all with red eyesCross 2: Males with purple eyes × females with vermilion eyes212 male offspring with vermilion eyes221 female offspring with red eyesExplain the pattern of inheritance based on these results. Whatadditional crosses might you make to confirm your hypothesis?
In Drosophila, sepia colored eyes are due to a recessive allele s and red eyes are due to a dominant allele S. If females with sepia eyes are crossed with homozygous males with red eyes, what phenotypic proportions will F1 y F2 respectively?
Consider this cross in pea plants: Tt Rr yy Aa × Tt rr Yy Aa, whereT = tall, t = dwarf, R = round, r = wrinkled, Y = yellow, y = green,A = axial, a = terminal. What is the expected phenotypic outcomeof this cross? Have one group of students solve this problem bymaking one big Punnett square, and have another group solve it bymaking four single-gene Punnett squares and using the multiplication method. Time each other to see who gets done first.
In rabbits, black hair is due to a dominant allele B and brown hair to its recessive allele b. Short hair (H) is dominant to long hair (h). Show punnet squares In a cross between a homozygous black, longhaired rabbit and a brown, homozygous shorthaired one, what would the F1 generation look like? If you did not know the genotype of an F1 rabbit, you could determine its genotype by a test cross in which it is crossed with an animal with which phenotype AND genotype? If you carried out this test cross (from 2, using the F1 from 1), what phenotypes and in what ratio would you expect? What phenotypes in what ratio would be expected in the F2 generation of the cross in point 1?
The production of eye-color pigment in Drosophila requires the dominant allele A. The dominant allele P of asecond independent gene turns the pigment to purple,but its recessive allele leaves it red. A fly producing nopigment has white eyes. Two pure lines were crossedwith the following results:P red-eyed female white-eyed maleF1 purple-eyed femalesred-eyed malesF1 F1purple eyed 38red eyed 38white eyed 28F both males and females: 2Explain this mode of inheritance, and show the genotypesof the parents, the F1, and the F2.
Fruit flies can have straight wings (S) or curly wings (s), and they can have be female XX or male XY. (A) For a standard monohybrid cross (Ss ´ Ss), what proportion of the offspring will have the genotype ss? (Express the proportion as a simple fraction) (B) For the following cross (SsXX ´ SsXY), what proportion of the offspring will have the genotype Ss? (Express the proportion as a simple fraction) (C) What proportion will have the genotype XX? (Express the proportion as a simple fraction) (D) What proportion will have the genotype SsXX? (Express the proportion as a simple fraction)SHOW YOUR WORK
Do a Punnett square for a cross between a homozygous red-eyed female (XR XR ) and a white-eyed male (Xr Y). What would be the genotypes of the female F1 flies? ____ phenotype? ______ What would be the genotypes of the male F1 flies? ___ phenotype? _______ Do a Punnett square for the F2 results if one of the F1 females mated with one of the F1 males. *To show results of sex-linked traits: Divide phenotypes into males and females first, keep results as fractions (or %). List the phenotypes, with the corresponding genotype (in parentheses) next to each phenotype. Males: Females: A sex-linked trait in humans: hemophilia = blood clotting disorder. Normal clotting (XN) is dominant to hemophilia (Xn). Do a Punnett square for a normal clotting (homozygous dominant) woman and a man with hemophilia.
You are studying ear shape in dogs (with XY se x determination) and cross a true-breeding pointed-ear female to a true-breeding floppy-ear male and collect all pointy-ear male and female offspring. Your colleague suspects that the two phenotypes may be caused by alleles of one X-linked gene. What sort of cross would you do to determine whether this is an X-linked trait? Name it and describe it. What offspring phenotypic ratio would you expect in that cross if the green allele is a dominant X-linked allele? Make sure to label your ratio with all relevant phenotypes. How would the result of your cross (from A) be different if the trait is autosomal
In humans, the genetic disease cystic fibrosis is caused by a recessive allele (a). The normal (healthy) allele is dominant (A). What is the genotype of someone who has cystic fibrosis? What are the two different genotypes that a healthy person could have? If two people were both heterozygous for the cystic fibrosis gene, what fraction of their children would be likely to have this disease? Hint: Draw a Punnett square to figure it out.