Question
Asked Dec 18, 2019
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In each of the equation below, find all solutions [0, 2π)

a. 2sin2x=1

b. √3 cscxm - 2=0

c. sin2x-7sinx=0

d. cos2x+2cosx+1=0

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Expert Answer

Step 1

Given: -

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a. 2sin? x = 1 b. 3 csc x - 2 = 0 c. sin? x – 7sin x = 0 d. cos x + 2cos x +1=0

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Step 2

To find: -

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The solutions of above equations in the interval [0,27)

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Step 3

Calculation: -

Pa...

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2sin? x =1 sin? x=: sin x=±- V2 Taking sin x = л Зл x=-,- 4 4 Taking sin x = 5л 7л x= - л Зл 5л 7л 4' 4'4' 4 The solution of 2 sin x =1 is x= in the interval [0,27).

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Tagged in

Math

Calculus