In Exercises use the surface integral in Stokes' Theorem to calculate the circulation of the field F around the curve C in the indi- cated direction. 7. F = x²i + 2xj + z²k C: The ellipse 4x² + y² = 4 in the xy-plane, counterclockwise when viewed from above 8. F = 2yi + 3xj – z²k C: The circle x² + y? = 9 in the xy-plane, counterclockwise when viewed from above 9. F = yi + xzj + x²k C: The boundary of the triangle cut from the planex + y + z = 1 by the first octant, counterclockwise when viewed from above 10. F = (y² + z?)i + (x² + z²?)j + (x² + y²)k C: The boundary of the triangle cut from the plane x + y + z = 1 by the first octant, counterclockwise when viewed from above

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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In Exercises
use the surface integral in Stokes' Theorem to
calculate the circulation of the field F around the curve C in the indi-
cated direction.
7. F = x²i + 2xj + z²k
C: The ellipse 4x² + y² = 4 in the xy-plane, counterclockwise
when viewed from above
8. F = 2yi + 3xj – z²k
C: The circle x² + y? = 9 in the xy-plane, counterclockwise
when viewed from above
9. F = yi + xzj + x²k
C: The boundary of the triangle cut from the planex + y + z = 1
by the first octant, counterclockwise when viewed from above
10. F = (y² + z?)i + (x² + z²?)j + (x² + y²)k
C: The boundary of the triangle cut from the plane x + y + z = 1
by the first octant, counterclockwise when viewed from above
Transcribed Image Text:In Exercises use the surface integral in Stokes' Theorem to calculate the circulation of the field F around the curve C in the indi- cated direction. 7. F = x²i + 2xj + z²k C: The ellipse 4x² + y² = 4 in the xy-plane, counterclockwise when viewed from above 8. F = 2yi + 3xj – z²k C: The circle x² + y? = 9 in the xy-plane, counterclockwise when viewed from above 9. F = yi + xzj + x²k C: The boundary of the triangle cut from the planex + y + z = 1 by the first octant, counterclockwise when viewed from above 10. F = (y² + z?)i + (x² + z²?)j + (x² + y²)k C: The boundary of the triangle cut from the plane x + y + z = 1 by the first octant, counterclockwise when viewed from above
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