In Figure (a) below, a particle of charge +Q producesan electric field of magnitude Epart at point P, atdistance R from the particle. In Figure (b), that sameamount of charge is spread uniformly along a circulararc that has radius R and subtends an angle 8. Thecharge on the arc produces an electric field ofmagnitude Earc at its center of curvature P. For whatvalue of 0 (inº) does Earc = 0.75Epart? (Hint: You willprobably resort to a graphical solution.)+Q||▬▬R—-|Number iP(a)!+Q{{0/2VR8/24(b)UnitsO(degree

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In Figure (a) below, a particle of charge +Q produces an electric field of magnitude Epart at point P, at distance R from the particle. In Figure (b), that same amount of charge is spread uniformly along a circular arc that has radius R and subtends an angle 9. The charge on the arc produces an electric field of magnitude Earc at its center of curvature P. For what value of 0 (in º) does Earc = 0.75Epart? (Hint: You will probably resort to a graphical solution.)

In Figure (a) below, a particle of charge +Q produces an electric field of magnitude Epart at point P, at distance R from the particle. In Figure (b), that same amount of charge is spread uniformly along a circular arc that has radius R and subtends an angle 9. The charge on the arc produces an electric field of magnitude Earc at its center of curvature P. For what value of 0 (in º) does Earc = 0.75Epart? (Hint: You will probably resort to a graphical solution.)