In Go Lang 4. Program stack. For the following code, answer the following questions. Assume we are putting everything for our function calls on the stack. · Show what a stack frame/activation record for main() looks like · Show what the stack frame/activation record for the 2nd call to ctTarg look like? (Yes, this means you can skip the other stack frames) · We note that targ does not change value in any recursive call. Why doesn't the compiler just store targ once in one block of memory big enough to store a string? int ctTarg(string* list, int len, string targ) { if (len <= 0) return 0; if (*list == targ) return 1 + ctTarg(list + 1, len - 1, targ); return ctTarg(list + 1, len - 1, targ); } int main() { string pets[] = {"cat", "dog", "mouse", "cat"}; cout << ctTarg(pets, 4, "cat") << endl; }

In Go Lang 4. Program stack. For the following code, answer the following questions. Assume we are putting everything for our function calls on the stack. · Show what a stack frame/activation record for main() looks like · Show what the stack frame/activation record for the 2nd call to ctTarg look like? (Yes, this means you can skip the other stack frames) · We note that targ does not change value in any recursive call. Why doesn't the compiler just store targ once in one block of memory big enough to store a string? int ctTarg(string* list, int len, string targ) { if (len <= 0) return 0; if (*list == targ) return 1 + ctTarg(list + 1, len - 1, targ); return ctTarg(list + 1, len - 1, targ); } int main() { string pets[] = {"cat", "dog", "mouse", "cat"}; cout << ctTarg(pets, 4, "cat") << endl; }

C++ Programming: From Problem Analysis to Program Design

8th Edition

ISBN:9781337102087

Author:D. S. Malik

Publisher:D. S. Malik

Chapter18: Stacks And Queues

Section: Chapter Questions

Problem 1TF

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The PostfixEvaluator class uses the java.util.Stack class to create thestack attribute. The java.util.Stack class is one of two stack implementationsprovided by the Java Collections API. We revisit the other implementation, theDeque interface, in Chapter 13.The evaluate method performs the evaluation algorithm described earlier, supported by the isOperator and evalSingleOp methods. Note that in the evaluatemethod, only operands are pushed onto the stack. Operators are used as they areencountered and are never put on the stack. This is consistent with the evaluation algorithm we discussed. An operand is put on the stack as an Integer object, insteadof as an int primitive value, because the stack collection is designed to store objects.When an operator is encountered, the two most recent operands are poppedoff the stack. As mentioned above, the first operand popped is actually the secondoperand in the expression and that the second operand popped is the first operandin the expression.…
Write a Java public static general function which doesn't belong to the Stack class, isGreaterThan that determines if one stack is greater than another stack. If the summation of every other item(starting at the top) from one stack is greater than the summation of every other item(starting at the top) from another, return true, otherwise, return false. After you call this method, both stacks should stay the same as they are called before. Receives: a Stack type argument S1 and another Stack type argument S2 Postcondition: If the summation of every other item (starting at the top) from S1 is greater than the summation of every other item (starting at the top) from S2, return true, otherwise, return false. Both S1 and S2 should stay the same as they are called before. public static boolean isGreaterThan(Stack S1, Stack S2)
TRUE or FALSE? Please answer the following question and state the reason why: Thank you! In a Dynamic Stack, the pointer top stays at the head after a push operation. During a Pop operation in Static Stack, the elements are being moved one step up. In a dynamic implementation of stack, the pointer top has an initial value of null. STL empty function will yield a value of true if the stack has elements.
Please explain the distinction between the restricted version of the stack and the unlimited version of the stack.
Write a program for Stack (Array-based or linked list-based) in Python. Test the scenario below with the implementation and with the reasoning of the answer. Make comments with a short description of what is implemented. Include source codes and screen-captured outputs. Stack: A letter means doing a push operation and an asterisk means doing a pop operation in the below sequence. Give the sequence of letters that are returned by the pop operations when this sequence of operations is performed on an initially empty stack. A*BCE**F*GH***I*
For this project, you will read an infix expression, convert it to postfix, evaluate the postfix expression, and print out the answer. You will need to define and implement your own Stack class and a Calculator class. Your Stack class should support standard stack operations, which you can implement with either a linked list or an array. You should use a class template Stack in C++, but an integer Stack class would work as well since a character would be considered a subset of integers. Your Calculator class stores an infix operation and it provides the public operations below. Feel free to add private operations and data. The Calculator class should use a character stack to convert infix to postfix (storing operators) and then uses an integer stack to evaluate the expression (storing operands). C++ C++ C++ C++ C++ C++ C++ C++ C++ C++ C++ C++ C++ C++ C++ C++ C++ C++ C++ C++ C++ C++ C++ C++ C++ C++ C++ C++ C++ C++ C++ C++ C++ C++ C++ C++ C++ C++ C++ C++ C++ C++ C++ C++ C++ C++ C++ C++…
Question#3.Write a Python program to reverse a stack using recursion. Problem Solution Hints: 1. Create a class Stack with instance variable items initialized to an empty list. 2. Define methods push, pop, is_empty and display inside the class Stack. 3. The method push appends data to items. 4. The method pop pops the first element in items. 5. The method is_empty returns True only if items is empty. 6. The method display prints the elements of the stack from top to bottom. 7. Define function insert_at_bottom which takes a stack and a data item as arguments. 8. The function insert_at_bottom adds the data item to the bottom of the stack using recursion. 9. Define function reverse_stack which takes a stack as argument. 10. The function reverse_stack reverses the stack using recursion. 11. Create an instance of Stack, push data to it and reverse the stack.
How is using the stack STL compared to hard coding the implementation of the stack through an array or a linked list? Use code (with screenshots) to expound further in your explanation. (C++)
Can you explain in detail, line by line, what the attached algorithm is doing? I need further understanding. For further clarification the prompt asks the following: Write an algorithm Replace that takes a stack and two items. If the first item is in the stack, replace it with the second item, leaving the rest of the stack unchanged.
You are given N elements and your task is to Implement a Stack in which you can get a minimum element in O(1) time. Example 1: Input: push(2) push(3) pop() getMin() push(1) getMin() Output: 2 1 Explanation: In the first test case for query push(2) Insert 2 into the stack. The stack will be {2} push(3) Insert 3 into the stack. The stack will be {2 3} pop() Remove top element from stack Poped element will be 3 the stack will be {2} getMin() Return the minimum element min element will be 2 push(1) Insert 1 into the stack. The stack will be {2 1} getMin() Return the minimum element min element will be 1.
Refer to the code fragment below and convert the following Queue structure into a Stack structure. You should create a reference called S1 for the stack structure. Code: Queue Q1 = new LinkedList (); Q1.add(“Sandra”); Q1.add (15); Q1.add (200); Q1.add (‘# ‘); Q1. remove (); System.out.println(Q1); System.out.println(Q1.peek()); Q1.add(“Mary”); System.out.println(Q1);
Convert the following infix notation to its postfix notation. You must show the stack contents in your simulation. (5+ x!=d)==|{(3!=e*6) && (1==5/5} != 4 -51 Priority: */,% (high) t, = I= && (low)