In humans, the allele for brown eye color (B) is dominant to thatfor blue eye color (b). If two heterozygous parents produce children, what are the following probabilities? A. The first two children have blue eyes.B. A total of four children, two with blue eyes and the other twowith brown eyes.C. The first child has blue eyes, and the next two have brown

In humans, the allele for brown eye color (B) is dominant to thatfor blue eye color (b). If two heterozygous parents produce children, what are the following probabilities? A. The first two children have blue eyes.B. A total of four children, two with blue eyes and the other twowith brown eyes.C. The first child has blue eyes, and the next two have brown

Name: In humans, the allele for brown eye color (B) is dominant to thatfor b
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Description: In humans, the allele for brown eye color (B) is dominant to thatfor blue eye color (b). If two heterozygous parents produce children, what are the following probabilities?A. The first two children have blue eyes.B. A total of four children, two with

Biology (MindTap Course List)

11th Edition

ISBN:9781337392938

Author:Eldra Solomon, Charles Martin, Diana W. Martin, Linda R. Berg

Publisher:Eldra Solomon, Charles Martin, Diana W. Martin, Linda R. Berg

Chapter11: The Basic Principles Of Heredity

Section: Chapter Questions

Problem 2TYU: The F1 flies described in question 1 were mated with brown-eyed flies from a true-breeding line....

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In humans, the allele for brown eye color (B) is dominant to blue eye color (b). If two heterozygous parents produce children, what are the following probabilities? **Note, this problem way over simplifies eye color, which is influenced by at least eight different genes. a. A total of four children, two with blue eyes and the other two with brown eyes. b. The first child has blue eyes, and the next two have brown eyes.
In man, the allele for normal color (A) is dominant to the allele for albinism (a). A normal man whose father was albino married a normal woman whose mother was albino. a. What are the chances that their first child will be albino? b. What are the chances their second child will be albino?
Alkaptonuria is a metabolic disorder in which affected people produce black urine. Alkaptonuria results from an allele (a) that is recessive to the allele for normal metabolism (A). Sally has normal metabolism, buther brother has alkaptonuria. Sally’s father has alkaptonuria, and her mother has normal metabolism. Q. If Sally marries a man with alkaptonuria, what is the probability that their first child will have alkaptonuria?
In humans, potential or expecting parents can be tested for the presence of the allele for the autosomal recessive cystic fibrosis. Which combination of parents are LEAST likely to produce a child with cystic fibrosis? A. 2 parents with cystic fibrosis B. 2 parents without cystic fibrosis C. 1 parent without cystic fibrosis and 1 with cystic fibrosis D. 2 parents who do not know if they have cystic fibrosis
In certain species of flies, eye color is controlled by sim-·ple dominance by a single pair of alleles. A red-eyed fly was crossed with a white-eyed fly, both of whose parents had white eyes. All of their offspring (both female and male) had red eyes.a. Which is dominant, the allele for red eyesor the allele for white eyes?b. What is the genotype of the white-eyed parents?c. If the white-eyed parent was mated with one of the red-eyed offspring, what phenotypic ratio wouldyou expect regarding eye color?
Given a cross between these two parents: BbCcDDEEFfGgHhjj x BbCcddEeFfGgHHjj where traits B, E, H, J exhibit Mendelian inheritance; C, and F exhibit incomplete dominance; D, and G exhibit co-dominance answer the following: How many phenotypes can be expected from the cross?
In the pedigree shown in Figure Q19–14, the first born in each of three generations is the only person affected by a dominant genetically inherited disease, D. your friend concludes that the first child born has a greater chance of inheriting the mutant D allele than do later children.A. According to Mendel’s laws, is this conclusion plausible?B. What is the probability of obtaining this result by chance?
The American Curl is a breed of cat that has curly ears. The allele for the curly ears is dominant (E). Suppose a cat with the heterozygous genotype is bred to a female cat with the homozygous recessive genotype. Fill out a Punnett Square and answer the following questions. What is the phenotypic ratio of this punnett square? If this cross produces six kittens, how many of them will have curly ears? ________
Based on the allelic gene interaction in Australian milking shorthorn cattle breeds, the mating of a red cattle (RR) and white cattle is depicted in the picture below. What is gene interaction involved in this resulting coat color of the offspring? see photo attached a. Complete dominance b. Incomplete dominance c. Codominance d. Additive gene action
Albinism is inherited as a recessive trait in humans. If the parents are both heterozygous for the trait, what is the probability of obtaining the following: a. 3 albino children? b. 2 normal girls? c. 4 albino boys? d. first 4 children will be normal and the last 2 children will be albino? e. 4 normal children and 2 albinos in any order?
The allele for red feather color in pigeons (B), is dominant to the allele for brown feathers (b.) A red pigeon that has a red parent and a brown parent is mated with a brown pigeon. a.) Give the genotypes of the two pigeons being mated. b.) what proportion of the F1 progeny would be expected to have brown feathers? Assume that these pigeons produce five young pigeons. c.) what is the probability that all five will be red? d.) What is the probability that 3 will be red and 2 will be brown?
In a particular human family, John and his motherboth have brachydactyly (a rare autosomal dominant allele causing short fingers). John’s father hasHuntington disease (another rare autosomal dominant allele). John’s wife is phenotypically normaland is pregnant. Two-thirds of people who inheritthe Huntington (HD) allele show symptoms by age50, and John is 50 and has no symptoms.Brachydactyly is 90% penetrant.a. What are the genotypes of John’s parents?b. What are the possible genotypes for John? Howlikely is John to have each of these genotypes?c. What is the probability the child will express bothbrachydactyly and Huntington disease by age 50 ifthe two genes are unlinked?d. How will your answer to part (c) change if insteadthese two loci are 20 m.u. apart?