In mammoths, assume that spotted skin (S) is dominant over non-spotted skin (s) and that wooly hair (W) is dominant over non-wooly hair (w). A cross between a heterozygous spotted, non-wooly mammoth and a heterozygous wooly-haired, non-spotted mammoth. How many offspring will be spotted, non-wooly mammoth? How many offspring will be non-spotted, non-wooly mammoth? How many offspring will be spotted, wooly mammoth? How many offspring will be non-spotted, wooly mammoth?
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- In humans, widow's peak (H) is dominant over a continuous hairline (h), and short fingers (F) are dominant over long fingers (f). Two heterozygous individuals with widow's peak and short fingers want to have a child with continuous hairline and long fingers. Is this possible?Phenotypically wild-type female Drosophila, whose mothers had spineless bristles (ss) and fathers had ebony bodies (e), produced the following offspring when crossed to homozygous males with ebony bodies and spineless bristles: 43 ebony bodies and spineless bristles 49 wild type 336 ebony bodies, wild type bristles 328 spineless bristles and wild type body color What is the map distance between the ebony body and spineless bristles loci? Group of answer choices 12.2 43.9 24.4 87.8 6.1In man, assume that spotted skin (S) is dominant over non-spotted skin (s) and that wooly hair (W) is dominant over non-wooly hair (w). Cross a marriage between a heterozygous spotted, non-wooly man with a heterozygous wooly-haired, non-spotted woman. Give genotypic and phenotypic ratios of offspring. In horses, black is dependent upon a dominant gene, B, and chestnut upon its recessive allele, b. The trotting gait is due to a dominant gene, T, the pacing gait to its recessive allele, t. If a homozygous black pacer is mated to a homozygous chestnut trotter, what will be the appearance of the F1 generation?
- When a Chinese hamster with white spots is crossed with another hamster that has no spots, approximately 12 of the offspring have white spots and 12 have no spots. When two hamsters with white spots are crossed, 23 of the offspring possess white spots and 13 have no spots. Q. What is the genetic basis of white spotting in Chinese hamsters?In fruit flies, gray body (G) is dominant to black body (g). If a male with a black body mates with a female that is homozygous dominant for her gray body what are the possible genotypes and phenotypes of their offspring? Complete the Punnett square below. What is the expected phenotypic ratio among the offspring?In pigs, the presence of a white belt around the body is dominant to a solid body color. If a belted sow (female) is mated with a solid boar (male), and the sow has a litter of 10 piglets, half of them solid and half belted, what would be the genotype of the sow?
- In cocker spaniels, solid coat color is dominant over spotted coatcolor. If two heterozygous dogs were crossed to each other, whatwould be the probability of the following combinations of offspring?A. A litter of five pups, four with solid fur and one with spotted fur.B. A first litter of six pups, four with solid fur and two with spotted fur, and then a second litter of five pups, all with solid fur.C. A first litter of five pups, the firstborn with solid fur, and thenamong the next four, three with solid fur and one with spottedfur, and then a second litter of seven pups in which the firstborn is spotted, the second born is spotted, and the remainingfive are composed of four solid and one spotted animal.D. A litter of six pups, the firstborn with solid fur, the second bornspotted, and among the remaining four pups, two with spottedfur and two with solid furIn a species of dog, plaid color is represented by P and purple by p, short -tailed is T and long-tailed is t. What are the genotypes of a male who is purple with a long tail, and a female who is homozygous dominant for both traits? Which answer below is true? PpTT & PPTT pptt & PPTT short-tailed purple & long tailed plaid male: purple w/ long tail & female: plaid w/ short tailWithin a mouse population, the black fur allele (B) is dominant to the white fur allele (b) and the short whisker allele (S) is dominant to the long-whisker allele (s). A heterozygous black-furred short-whiskered mouse is crossed with a homozygous white-furred long-whiskered mouse. What percentage of the offspring will be black-furred with long whiskers?
- The long hair of Persian cats is recessive to the short hair of Siamese cats, but the black coat colour of Persians is dominant to the black-and-tan coat of the Siamese. a) If a true-breeding black long-haired Persian is mated with a true-breeding black-and-tan short-haired Siamese, what are the predicted phenotypes of the cats in the F1 generation? b) If two of the F1 generation cats are then mated, what is the chance of obtaining a long-haired black-and-tan cat in the F2 generation? Your answerIn the multiple-allele series that determines coat color inrabbits, c+ encodes agouti, cch encodes chinchilla (a beigecoat color), and ch encodes Himalayan. Dominance is inthe order c+ > cch > ch. In a cross of c+/cch × cch/ch, whatproportion of progeny will be chinchilla?In jellyfish, let's say that long tentacles are produced by a sex-influenced allele that is dominant in males and recessive in females. Let B1 = long and B2 = short. Which of the following correctly diagrams a cross between a female with long tentacles and a male with short tentacles? O B1B1XX X B1B2XY O B1B2 XX X B1B2 XY O females with long tentacles do not exist, so this cross is impossible O B1B1 XX X B2B2 XY O X(B1) X(B2) x X(B2) Y