In microprocessor, zero flag is set to 1 when the result is zero the result is positive O the result is nonzero
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- A(n) __________ is a storage location implemented in the CPU.Convert given code to LEGv8 code:int f, g, y //global 64-bit variablesint sum (int a, int b) { // at memory address X0+1000.return (a +b)} int main (void) // at memory address X0 + 800{f=2;g=3;y= sum (f, g);return y;}Convert this code, making valid assumptions about registers and register use. Notethat brackets and global variable declarations are not affecting the addresses of the instructionsin memory.The control signal Ep or iEnableoutput allows the program counter to decrement its value. True False The control signal Ep or iEnableoutput sends the content of the program counter to the W bus. True False A tri-state buffer is needed for all data going to the W bus. True False In using 'assign' statement in Verilog, the left hand side must always be a register. True False In declaring a register in Verilog, the following format must be followed: reg [LSB:MSB] identifier; True False
- Answer the given question with a proper explanation and step-by-step solution. PLEASE PAY ATTENTION TO THE DATA TYPES AND FOLLOW THE CODE AND DIRECTIONS EXACTLY Convert the following C++ program into an x86 assembly language program.Comment the start of each "code block" that performs one of the listed mathematical calculations.Comments go to the right of the actual code, all starting on the same column.Post ONLY your ASM file here to Blackboard when complete. // Global variableschar a = 5;char b = 6;char c = 7;char d = 8;char e = 2;char f = 3;char g = 1;char h = 4;// Codeint main(){ --h; c = g + h; d = e + 22 - c - b; g = -h; ++b; a = g + d - 15; b = a + 92 - b; h = d + (-f) - d; // Move a into the eax register // Move b into the ebx register // Move c into the ecx register // Move d into the edx register // Call the DumpRegs function // Move e into the eax register // Move f into the ebx register // Move g into the ecx register…Write a program, in assembly language format, to hold a character set at a specific memory location. Each character is entered via the keyboard and ends with the character '!'. Furthermore, the set of characters that have been stored in memory is displayed on the monitor screen. Hint: use the interrupts mentioned in question no 2 above. For example: from the keyboard type 'I', 'L', 'K', 'O', 'M', '!' ; then save it in a certain memory location and the screen display becomes ILKOM. Instructions: create a program in the form of procedures.IN asmly language please Pretty please with successful build screen shot and output 1.Using the AddTwo program from Section 3.2 as a reference, write a program that calculates the following expression, using registers: A = (A + B) − (C + D). Assign integer values to the EAX, EBX, ECX, and EDX registers. Note: you can hard code integer literal onto the registers, e.g. mov eax,55 ; AddTwo.asm - adds two 32-bit integers.; Chapter 3 example .386.model flat,stdcall.stack 4096ExitProcess proto,dwExitCode:dword .codemain proc mov eax,5 add eax,6 invoke ExitProcess,0main endpend main 2. Listing File for AddTwoSum Generate a listing file for AddTwoSum.asm(in 3.4.3 of the text) and write a description of the machine code bytes generated for each instruction. You can write your descriptions directly over the .lst file. You might have to guess at some of the meanings of the byte values. Submit the .lst file with your description over it.…
- What will be the contents of BX after the following instructions execute?mov bx,5stcmov ax,60hadc bx,axHere are some registers and storage locations during the run of a program.For this example, all numbers are hex.eax contains 300ebx contains 3000The doubleword at memory location 300 contains 500The doubleword at memory location 10 contains 70 What is in eax after the command addl $10, %eax executes? a. 310 b. 510 c. 370f R0 = 0x20008000, after executing STMIA r0!, {r3, r9, r7, r1, r2}, register r7 will be stored in memory starting from which bases. Please choose one:A. R0 = 0x2000800CB. R0=0x20008004C. R0= 0x20008014D. R0 = 0x20008010E. R0 = 0x20008008
- Please this question answered by this website but not appropriate answer because in c++ I want to answer in Assemly language to 8086 processor and 16 bit registers only Please solve it and send me please ? This question: Write a program to find the factors of a number and store the result at address 200 in memory.Sample Answer: I wrote a program to store factors of 60 at 200. (you should choose anynumber but greater than 20.WOLcUID wwreyg-100Ax-0060 BX=0030 CX-000 DX-0000 SP-0OFD BP=0900 SI=0000 DI-0209DS-073F ES-073P SS=073PF CS-973F IP-0110 NU UP EI PL ZR NA PE NC073F:011C CCd 2873F:020002 03 04 06 08 OC 10 18-20 00 00 00 00 00 00 00073F:0210 00 00 00 00 00 00 00 00-00 00 00 00 00 00 00 00973F:0220 00 00 00 00 00 00 00 0-00 00 00 00 00 00 00 00073F:0230 00 00 00 00 00 00 00 00-00 00 00 00 00 00 00 0873F :0240 00 00 00 00 00 00 00 0-00 00 00 00 00 00 00 00o73P:250 00 00 00 00 08 00 0 00-00 00 00 00 00 00 00 00073F873F:0270 00 00 00 00 00 00 00 00-00 00 00 00 00 00 00 00f 400 40c…A fragment of code is given to compare text in the field alpha with a text in the field beta: .data alpha db 12 dup(?) beta db ’abrakadabra’, 0 ; ::: .code ; ::: mov esi, 0 mov ecx, 12 ns: mov dl, alpha[esi] cmp dl, beta[esi] jne wrong ;=====MISSING==== loop ns ; ::: wrong: Choose missing instruction to insert in the code line marked by the comment “MISSING”.Write a MIPS program (please show the whole code with comments)Given the following data definition statements, compute the addresses of arr2, arr3, str1, and str2, given that the address of arr1 is 0x10010000. Show your steps for a full mark. Select “Show Labels Window (symbol table)” from the Settings menu in MARS to check the values of your computed addresses. .data arr1: .word 5:20 arr2: .half 7, -2, 8, -6 arr3: .space 100 str1: .asciiz "This is a message" str2: .asciiz "Another important string"
