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In Problems 5–44, solve each logarithmic equation. Express irrational solulldNs In CAuoi ji 6. log (x + 6) = 1 = log, 15 7. log2(5x) = 4 d olo 10. log5(2x + 3) = 5. log, x = 2 log, 3 13. logs|2x – 1| = log, 13 9. log4 (x + 4) 8. log3 (3x – 1) = 2 11. log.x = 3 12. log2|x - 7| = 4 16. -2 log4 x = log4 9 %3D 14. logg/3x + 4| = log/5x - 12| 15. log7x = 3 log, 2 19. 2 log6(x - 5) + log, 9 = 2 A 17. 3 log2 x = -log2 27 18. 2 logs x = 3 logs 4 20. 2 loga (x + 4) – log; 9 = 2 21. log x + log (x + 15) = 2 22. log x + log (x – 21) = 2

In Problems 5–44, solve each logarithmic equation. Express irrational solulldNs In CAuoi ji 6. log (x + 6) = 1 = log, 15 7. log2(5x) = 4 d olo 10. log5(2x + 3) = 5. log, x = 2 log, 3 13. logs|2x – 1| = log, 13 9. log4 (x + 4) 8. log3 (3x – 1) = 2 11. log.x = 3 12. log2|x - 7| = 4 16. -2 log4 x = log4 9 %3D 14. logg/3x + 4| = log/5x - 12| 15. log7x = 3 log, 2 19. 2 log6(x - 5) + log, 9 = 2 A 17. 3 log2 x = -log2 27 18. 2 logs x = 3 logs 4 20. 2 loga (x + 4) – log; 9 = 2 21. log x + log (x + 15) = 2 22. log x + log (x – 21) = 2

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section5.6: Exponential And Logarithmic Equations
Problem 64E
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7,13,19
3. Approximate the solution(s) to x = x² utility. (pp. B6-B8) 5 using a grupi U LU grapilng utim ) Skill Building In Problems 5–44, solve each logarithmic equation. Express irrational solutions in exact form. 7. log2 (5x) = 4 6. log (x + 6) = 1 log, 15 5. log4 x = 2 dt oto 10. log5(2x + 3) = log, 3 8. log3 (3x – 1) = 2 9. log4 (x + 4) no w d 13. logs 2x – 1| = log5 13 11. log4|x| = 3 12. log2|x 7 = 4 16. -2 log4 x = log4 9 14. log9|3x + 4| = log9|5x – 12| 15. - log7 x = 3 log7 2 19. 2 log6(x - 5) + log, 9 = 2 17. 3 log2 x = -log2 27 18. 2 logs x = 3 log5 4 22. log x + log (x – 21) = 2 20. 2 log3 (x + 4) – log3 9 = 2 21. log x + log (x + 15) = 2 25. log2 (x + 7) + log2(x + 8) = 1| 28. logs (x + 3) = 1 – log3(x – 1) 31. log9 (x + 8) + log,(x + 7) =2 34. log4 (x – 9) – log,(x + 3) = 3 36. log, x + log, (x – 2) = loga(x + 4) 38. log3 x - 2 log3 5 = log3(x + 1) – 2 log; 10 23. log (7x + 6) = 1 + log (x – 1) 24. log (2x) – log (x – 3) = 1 26. logo(x + 4) + log6(x + 3) = 1 27. logs (x + 6) = 1 – logs(x + 4) - 29. In x + In (x + 2) = 4 30. In (x + 1) – In x = 2 32. log2 (x + 1) + log2(x + 7) = 3 33. log1/3 (x + x) – log1/3 (x² – x) = -1 35. log. (x – 1) – log.(x + 6) = loga(x - 2) – loga(x + 3) 37. 2 log5 (x – 3) – log5 8 = log5 2 39. 2 log, (x + 2) = 3 log, 2 + log, 4 40. 3(log7 x – log, 2) = 2 log, 4 41. 2 log13 (x + 2) = log13(4x + 7) deups latnonogx 43. (log3 x)2 – 3log3x = 10 i booubo 42. log (x – 1) = log 2 44. In x - 3V In x + 2 = 0 Bob mo ghbiozerc pe aojogo
Transcribed Image Text:3. Approximate the solution(s) to x = x² utility. (pp. B6-B8) 5 using a grupi U LU grapilng utim ) Skill Building In Problems 5–44, solve each logarithmic equation. Express irrational solutions in exact form. 7. log2 (5x) = 4 6. log (x + 6) = 1 log, 15 5. log4 x = 2 dt oto 10. log5(2x + 3) = log, 3 8. log3 (3x – 1) = 2 9. log4 (x + 4) no w d 13. logs 2x – 1| = log5 13 11. log4|x| = 3 12. log2|x 7 = 4 16. -2 log4 x = log4 9 14. log9|3x + 4| = log9|5x – 12| 15. - log7 x = 3 log7 2 19. 2 log6(x - 5) + log, 9 = 2 17. 3 log2 x = -log2 27 18. 2 logs x = 3 log5 4 22. log x + log (x – 21) = 2 20. 2 log3 (x + 4) – log3 9 = 2 21. log x + log (x + 15) = 2 25. log2 (x + 7) + log2(x + 8) = 1| 28. logs (x + 3) = 1 – log3(x – 1) 31. log9 (x + 8) + log,(x + 7) =2 34. log4 (x – 9) – log,(x + 3) = 3 36. log, x + log, (x – 2) = loga(x + 4) 38. log3 x - 2 log3 5 = log3(x + 1) – 2 log; 10 23. log (7x + 6) = 1 + log (x – 1) 24. log (2x) – log (x – 3) = 1 26. logo(x + 4) + log6(x + 3) = 1 27. logs (x + 6) = 1 – logs(x + 4) - 29. In x + In (x + 2) = 4 30. In (x + 1) – In x = 2 32. log2 (x + 1) + log2(x + 7) = 3 33. log1/3 (x + x) – log1/3 (x² – x) = -1 35. log. (x – 1) – log.(x + 6) = loga(x - 2) – loga(x + 3) 37. 2 log5 (x – 3) – log5 8 = log5 2 39. 2 log, (x + 2) = 3 log, 2 + log, 4 40. 3(log7 x – log, 2) = 2 log, 4 41. 2 log13 (x + 2) = log13(4x + 7) deups latnonogx 43. (log3 x)2 – 3log3x = 10 i booubo 42. log (x – 1) = log 2 44. In x - 3V In x + 2 = 0 Bob mo ghbiozerc pe aojogo
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