In the circuit shown below, the current through the inductor is 1Ω 1/0° V -j1 Ω + 1/0° Α 1/0° Α 1 Ω 1/0° V + 1Ω
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![In the circuit shown below, the current through the
inductor is
1Ω
1/0° V
-j1 Ω
+
1/0° Α
1/0° Α
1 Ω
1/0° V
1Ω](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdb2a7238-f797-4569-96c2-3d4578de0c04%2F13a2c49b-e3ae-444d-ae5a-cab8be5f701f%2Fud94c3_processed.jpeg&w=3840&q=75)
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