In the circuit shown in figure, after the switch is open for a long time voltage across the capacitor at t=20 µs will be 10 2 + Vx - 3 V 0.5Vx ( Ve 20 uF +1
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- An AC circuit contains a 24 resistor, a 15.9-mH inductor, and a 13.3F capacitor connected in parallel. The circuit is connected to a 240-V, 400-Hz power supply. Find the following values. XL=XC=IR=AIL=AIC=AP=WVARsL=VARsC=IT=AVA=PF=%=You are an electrician working in an industrial plant. You discover that the problem with a certain machine is a defective capacitor. The capacitor is connected to a 240-volt AC circuit. The information on the capacitor reveals that it has a capacitance value of 10 mF and a voltage rating of 240 VAC. The only 10-mF AC capacitor in the storeroom is marked with a voltage rating of 350 WVDC. Can this capacitor be used to replace the defective capacitor? Explain your answer.9. 7.92. b) Suppose the inductor you chose in part (a) has an initial currentof 10 mA. Write an expression for the current through the inductorfor t≥0.
- A capacitor (0.02 F) is charged to 1 V and then connencted in series with an inductor (10 H) and a resitor (40 Ω). Initially, there is no current in the circuit. Find the amplitude, frequency, and phase of the charge on the capacitor and plot its graph.Determine the voltage across the capacitor, Vc(t) for t > 0 in the circuit below. The switch has been open for a long time, and the initial voltage across the capacitor is zero. Solve for the voltage with t = 2tauThe voltage across a 2µF capacitor is shown. Determine the waveformfor the capacitor current (a) Find mathematical expression of v(t) for 0 ≤ t ≤ 2 (b) Find mathematical expression of v(t) for 2 ≤ t ≤ 6 (c) Draw the waveform for the capacitor current.
- The current in the 50mH inductor in figure is known to be 100mA for t<0. The inductor voltage for t≥0 is given by the expression. Plot vL(t) and iL(t) for 0≤t<inf.1.) The circuit below is in steady state before the switch closes at t = 0. a)Determine the voltage across the capacitor for t > 0.For the figure, the circuit has reached steady state with the switch closed. Now the switch opens. a) Determine the time constant of the de-energized circuit.b) Determine the equation for the inductor current.c) Find the inductor current at time t = 17.8 µS.
- A 100-μF capacitor has a voltage given by v( t )=10−10 exp( −2t ) V. Find the power at t=0 and state whether the power flow is into or out of the capacitor. Repeat for t 2 =0.5 s.To measure the capacitance C of a capacitor, you attach the capacitor to a battery and wait until it is fully charged. You then disconnect the capacitor from the battery and let it discharge through a resistor of resistance RR. You measure the time T1/2 that it takes the voltage across the resistor to decrease to half its initial value at the instant that the connection to the capacitor is first completed. You repeat this for several different resistors. You plot the data as T1/2 versus R and find that they lie close to a straight line that has slope 9.00 μF. What is the capacitance C of the capacitor?The capacitor shown in the figure below is initially discharged. At t=0s the switch is moved to position B.Determine an expression for the voltage V across the capacitor for t≥0s.